David's age: x
Joshua: x + 5
Simon: (x+5) + 4 or x + 9
Simon's age + David's age = 15
(x+9) + (x) = 15
2x = 15 - 9
2x/2 = 6/2
x = 3
The ages of the boys:
David: x = 3 years old
Joshua: 3+5 = 8 years old
Simon: 3+9 = 12 years old
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solution:
Lets start with the most amount that could have been sold.......using guess and check, we can figure out that 290 salads could have been sold, while 8 cartons of milk would have been sold.
The least amount of salads that could have been sold were none.
so,
you have 0<s<290
at least none were sold, and at most 290 were sold
but I do believe you are missing part of the question
Answer:
The probability mass of X is 0.03
Step-by-step explanation:
If we set the winning requirement of your heads and my tails then the occurring possibility of both is 1/2 or 0.5.
Hence let us make a graph and use the figures to calculate the all the probabilities of you getting a heads.
Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.
The probability of winning start to drop as the winning amount increases.
X 0 1 2 3 4 5
Probability of Heads 0 0.50 0.25 0.13 0.06 0.03
Answer:
x=7
y=10.5
Step-by-step explanation:
1. You can apply the method of substitution, as you can see below:
- Substitute 
into the other equation and solve fo x:
- Substitute the value of x obtain into the first equation, then the value of y is:
