The ribbon would be 9 yards long
It’s c which is 28 degree Celsius
Answer:
we will change the problem in stages
pre-place 1 in x1 & x4, and 4 in x2, thus guaranteeing their minimum requirements.
now 19 pencils remain to be distributed
when there are no restrictions on distributing n identical objects to k distinct piles, the formula is (n+k-1)C(k-1) which here translates to 22C3
finally, we need to see that x3 = 5, so we place 6 in x3 (guaranteeing that it violates the condition), and subtract such violations, ie (22-6)C3 = 16C3
ans: 22C3 - 16C3 = 980
If you look at the figure, triangles XVW and ZYW are similar. So, you can use ratio and proportion to solve this problem. Notice that there are tick marks on th other two sides of the bigger triangles. That indicates that the like signs of ticks are equal. For example, that means XZ = ZW and that XW = 2XZ = 2ZW.
24.4/YZ = XW/ZW
24.4/YZ = 2ZW/ZW
24.4/YZ = 2
Solving for YZ,
<em>YZ = 12.2</em>