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maks197457 [2]
2 years ago
11

Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so

lution is made up of a 20% acid solution. The remaining three-quarters is made up of a solution of unknown concentration, c.
Which equation can be used to determine c, the unknown concentration?
Mathematics
2 answers:
labwork [276]2 years ago
6 0
<h2>30c + 10(0.2) = 40(0.32)</h2><h3 /><h3 /><h3 /><h3 /><h3>HURRY UP FAST YOU ARE TIMED STOP READING AND GO WHY ARE YOU STILL HERE OHH READING ME OK THAN I WILL STOP WRITING BUT GO</h3>
Sever21 [200]2 years ago
4 0
Taking the 3 solutions as 3 different terms, we can create an equation as follows:

Solution 1 : 10mL with 20% acid
Solution 2 : 30mL with x% acid
Solution 3 : 40mL with 32% acid

Since solution 1 + solution 2 = solution 3, let us substitute the given values we have:

10(0.2) + 30(x) = 40(0.32)
2 + 30x = 12.8

To solve for the unknown concentration x, we subtract 2 from both sides:
2 + 30x - 2 = 12.8 - 2
30x = 10.8

Dividing both sides by 30:
30x/30 = 10.8/30
x = 0.36

Therefore the unknown solution is 36% acid.
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