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Sphinxa [80]
2 years ago
5

Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4

Mathematics
1 answer:
crimeas [40]2 years ago
8 0

We have been given an expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}. We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, a^m\cdot a^n=a^{m+n}, we cab rewrite our given expression as:

\left( 4^{-2+(-3)} \right)^{3}

\left( 4^{-5} \right)^{3}

Now we will use exponent property (a^m)^n=a^{m\cdot n}to further simplify our expression.

\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}

\left( 4^{-5} \right)^{3}= 4^{-15}

Therefore, Chris made mistake in step 2.

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Find the point (x,y) of x2+14xy+49y2=100 that is closest to the origin and lies in the first quadrant.
Gala2k [10]

Notice that

x^2+14xy+49y^2=(x+7y)^2

so the constraint is a set of two lines,

(x+7y)^2=100\implies\begin{cases}x+7y=10\\x+7y=10\end{cases}

and only the first line passes through the first quadrant.

The distance between any point (x,y) in the plane is \sqrt{x^2+y^2}, but we know that \sqrt{f(x,y)} and f(x,y) share the same critical points, so we need only worry about minimizing x^2+y^2. The Lagrangian for this problem is then

L(x,y,\lambda)=x^2+y^2+\lambda(x+7y-10)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0

L_y=2y+7\lambda=0

L_\lambda=x+7y-10=0

We have

L_y-7L_x=2y-14x=0\implies y=7x

which tells us that

x+7y-10=0\iff x+49x=10\implies x=\dfrac15\implies y=\dfrac75

so that \left(\dfrac15,\dfrac75\right) is a critical point. The Hessian for the target function x^2+y^2 is

H(x,y)=\begin{bmatrix}2&0\\0&2\end{bmatrix}

which is positive definite for all x,y, so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is \sqrt{\left(\dfrac15\right)^2+\left(\dfrac75\right)^2}=2.

3 0
2 years ago
Write 0.00658 in standard form
Svetllana [295]

Answer:

0.00658 = 6.58 * 10^-3

Step-by-step explanation:

The standard form is a way of writing numbers easily in powers of 10.

To write a number in standard form, we have to move the decimal point to the front of the first non zero number.

Depending on the position of the decimal point to the first non zero number, movement can be towards the right or towards the left. When we move towards the right, our power of 10 will be negative, when we move in the left direction, our power of 10 will be positive

In this question, we shall be moving towards the right. Thus, our power of 10 is negative. We shall be moving towards the right 3 three times

Thus our power would be 10^-3

Thus our standard form will be 6.58 * 10^-3

Kindly note that another pointer is, if the value of our number to be written in standard form is less than zero, then the standard form will come in negative powers of 10. If the value of the number is greater or equal to 1 at least, then then the standard form will be in positive powers of 10

5 0
2 years ago
Drag each tile to the correct box. Not all tiles will be used.
Zina [86]

Answer:

$1,100 at 3.2% for 3 years -> $105.60

$990 at 3.15% for 4 years  -> $124.74

$1,025 at 2.8% for 5 years​ -> $143.5

Step-by-step explanation:

Simple interest formula is:

A = P*(1 + r*t)

where A if final account, P is principal, r is annual interest rate (as decimal) and t is time in years

Interest earned is A - P, then:

I = P*(1 + r*t) - P = P(1 + r*t - 1) = P*r*t

If P = $1100, r = 0.032 and t = 3, then:

I = 1100*0.032*3 = $105.6

If P = $990, r = 0.0315 and t = 4, then:

I = 990*0.0315*4 = $124.74

If P = $1025, r = 0.028 and t = 5, then:

I = 1025*0.028*5 = $143.5

5 0
2 years ago
A rectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.
Brilliant_brown [7]
The area of a rectangle is equal  L x  W   

4 cm longer than it is wide   L = 4 + <span>W
</span>
L x  W = 117     we replace L here 

(4 + <span>W ) x W = 117 
</span>
4W + W ^2  = 117 

<span>4W + W ^2  -117 = 0
</span>W ^2 +4 W -117 = 0

W² + 4W - 117 = 0

<span>
THEN u want to use the </span>use the quadratic formula
 

OR Factoring gives us

(W + 13)(W - 9) = 0

W = -13 or 9

But it can't be negative, so

W = 9  and L= 9+4 = 13
3 0
2 years ago
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Ulleksa [173]
The answer to your question is
5 0
2 years ago
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