Answer:
There are asymptotes at x = three-halves and x = negative one-third.
Step-by-step explanation:
f(x) = (x + 1)/ (6x^2 - 7x - 3)
= (x + 1)( / (6x^2 + 2x - 9x - 3)
= (x + 1) / (2x(3x + 1) - 3(3x + 1))
= (x + 1) / (2x - 3)(3x + 1)
Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.
Given inequality: 2y−x ≤ −6
Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied
Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied
Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.
Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.
Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.
Solutions are: (1, -4), (0, -3) , (2, -2)
Perhaps the easiest way to solve this problem is to convert 13 into a fraction that has the same denominator as 7 5/8.
Convert both to improper fractions:
7 5/8 turns into 61/8, and
13 turns into 104/8.
Then, subtract 61/8 from 104/8:
104/8-61/8=43/8.
Simplify (mixed fraction):
5 3/8.
The second ribbon has a length of 5 3/8 meters.
If jimmy made a profit of 15% than u would do 15,000 of 15% and that would be 2,250
but that would be Jimmy's profit
Now, what u would do to get how much the boat was sold, than u would do 15,000-2,250
and the answer will be 12,750
