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ira [324]
2 years ago
8

The family size bottle of sunscreen holds 121212 fluid ounces (\text{fl oz})(fl oz)left parenthesis, start text, f, l, space, o,

z, end text, right parenthesis of sunscreen. The regular bottle holds 75\%75%75, percent less.
How many fewer fluid ounces does the regular bottle of sunscreen hold?
\text{fl oz}fl oz
Mathematics
1 answer:
svlad2 [7]2 years ago
4 0
I cant understand your question
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a factory adds three red drops and two blue drops of coloring to white paint to make each pint of purple paint. the factory will
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So there are 8 pints in a us gallon, 2 drops of blue to make a pint of purple (2x8x50=800) and then 3 drops of red to make purple (3x8x50=1200) I think maybe I've missed a step but (800+1200=2000) so 2000 drops of red and blue combined to make 50 gallons of purple paint.

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This​ year, druehl,​ inc., will produce 57 comma 60057,600 hot water heaters at its plant in​ delaware, in order to meet expecte
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2 years ago
A man has 28 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 520 cents, how many d
nordsb [41]
Assuming x = dimes, y = quarters

x + y = 28 \\ 0.1x + 0.25y = 5.20

x + y = 28 \\ x = 28 - y

Substitute that into,
0.1(28 - y) + 0.25y = 5.20 \\ 2.8 - 0.1y + 0.25y = 5.20 \\0.15y = 2.4 \\ y = 16

Answer : He has 16 quarters.

Hope this helps. - M
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If 5 years ago nina was twice as old as sam, how soon from now will she be 1.5 times as old as sam? if x is sam's age 5 years ag
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7 0
2 years ago
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
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