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9966 [12]
1 year ago
15

A man bought a mobile phone for $800 and sold it for $1000. What was his profit as a percentage of the cost price ​

Mathematics
2 answers:
Butoxors [25]1 year ago
8 0

Answer:

25%

Step-by-step explanation:

Profit = Selling price - Cost price

= 1000 - 800

= $200

%Profit = Profit

_____. × 100. ( profit over cost price times 100)

Cost Price

= 200

____. × 100%

800

= 25%

bija089 [108]1 year ago
5 0

Answer:

1000/800 = 125% profit

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Find the values of x1 and x2 where the following two constraints intersect.
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Answer: x1 = 251/26, x2 = -111/26

Step-by-step explanation:

Hi!

As you can see in the figure, the point you are looking for is the intersection of two lines.

The intersection point is found solving this system of linear equations (the point must satisfy both equations):

9x_1 +7x_2=57\\4x_1 + 6x_2 = 13

You can solve it, for example, by the method of substitution:

\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)

Then plug x1 into equation 2, and solve for x2:

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Then you use the value of x2 to get x1:

x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\

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