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Elenna [48]
2 years ago
10

Consider triangle GHJ. Triangle G H J is shown. Angle G H J is a right angle. The length of the hypotenuse is 10 and the length

of another side is 5. What is the length of line segment HJ? 5 units 5 StartRoot 3 EndRoot units 10 units 10 StartRoot 3 EndRoot units
Mathematics
2 answers:
Murljashka [212]2 years ago
4 0

Length of segment HJ is 5√3 units

Step-by-step explanation:

Here, apply the Pythagorean relationship where sum of squares of the sides equals the square of the hypotenuse.

Given that the hypotenuse, c= 10 units, and one of the side, a=5 units, then the other side can be calculated as;

a²+b²=c²

5²+b²=10²

b²=10²-5²

b²=100-25

b²=75

b=√75 = √3*25 = √3 *√25 = √3 *5 = 5√3

Length of segment HJ is 5√3 units

Learn More

Pythagorean relationship:brainly.com/question/14532944

Keywords :triangle, right-angle, side, hypotenuse,line segment

#LearnwithBrainly

SOVA2 [1]2 years ago
4 0

Answer:

B

Step-by-step explanation:

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Simple random sampling method is used here.

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Given is that the evening host of a dinner dance reached into a bowl, mixed all the tickets around, and selected the ticket to award the grand door prize.

We can see that this is a simple random sampling method as every name on the ticket has an equal opportunity to get selected.

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What are two reasons someone might purposely choose a HIGHER monthly payment?
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A salesman has a base salary $2600 per month and makes 3 commission on each unit sold. If his total annual compensation is $48,0
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The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
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Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

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