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svlad2 [7]
2 years ago
13

A circus ring is the arena where much of the action takes place at a circus. The figure below shows a circus ring with the cente

r O. Arc AB and Arc DE are openings into the circle to enter and exit the ring.

Mathematics
1 answer:
Goshia [24]2 years ago
4 0

Answer:

Step-by-step explanation:

a) A diameter is a line that cuts a circle through at the centre. Line AD is a diameter.

Radius is half of a diameter i.e AD/2 = AO or OD

Chord is a straight line that touches the circumference of a circle. It doesn't pass through the centre like the diameter but cuts through the segments of a circle. Example of a chord is line FH

A tangent is a line that touches the circumference of a circle at just a point. It can touch any point on the circle. Example of a tangent line are AB and DE.

b) We must know that angle at a point or in a circle is 360°.

<EOH + <ECH = 360°

If <EOH = 131°

<ECH = 360° - 131°

<ECH = 229°

- <EFH falls in the circumference of the circle. Also know that, angle at the centre of a circle is twice angle at the circumference. Since <EOH is at the centre of the circle. <EFH = <EOH/2

<EFH = 131/2

<EFH = 65.5°

c) Given AB = DE, then <AB = <DE (oppositely directed angle).

Given <AOB = 20° then <DE = 20°

d) According to the diagram, <GFD = <GLD

If <GFD = 126°, then <GLD = 126°

e) Given HK = x+4, FK = x+14, GK = x, CK = x+32

From the diagram, CG = CK + KG

CG = x+32+x

CG = 2x+32

Also, FH = FK+HK

FH = x+14+x+4

FH = 2x+18

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A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18 \pi18π18, pi
katrin [286]

The area of the cross section of the column is 18 \pi \ m^2

Explanation:

Given that a building engineer analyzes a concrete column with a circular cross section.

Also, given that the circumference of the column is 18 \pi meters.

We need to determine the area of the cross section of the column.

The area of the cross section of the column can be determined using the formula,

Area= \pi r^2

First, we shall determine the value of the radius r.

Since, given that circumference is 18 \pi meters.

We have,

2 \pi r=18 \pi

   r=9

Thus, the radius is r=9

Now, substituting the value r=9 in the formula Area= \pi r^2, we get,

Area = \pi (9)^2

Area = 81 \pi

Thus, the area of the cross section of the column is 18 \pi \ m^2

5 0
2 years ago
Erik's disabled sailboat is floating stationary 3 miles east and 2 miles north of Kingston. A ferry leaves Kingston heading towa
sergij07 [2.7K]

Answer:

Step-by-step explanation:

Let's suppose that Ballard is an origin with coordinates (0;0)

Ballard is 8 miles south and 1 mile west of Edmonds ⇒ Edmonds is 1 mile east and 8 miles north of Ballard.

Thus, coordinates of Edmonds (0+1; 0+8) (1;8)

Edmonds is 6 miles due east of Kingston. So, is 6 miles due of Edmonds

Thus, Kingston coordinates (1-6;8) (-5:8)

Sailboat is 3 miles east and 2 miles north of kingston

So, coordinates of sailboat are (-5+3; 8+2) (-2;10)

a)

Ferry leaves Kingston towards Edmonds at mph and Edmonds is 6 miles due east of Kingston.

Initial ferry coordinates as calculated above are equal to Kingston coordinates (-5;8)

After 20 minutes the ferry turns to south.

This distance travelled (20min) is d=9mph*20/60h=3 miles

So, ferry travelled 3 miles toward east in 20 min

Then, coordinates became (-5+3;8+0) (-2;8)

Thus, we have a line connecting two points (-5;8) and (-2;8)

Line connecting them has an equation:

y-8 = (8-8)/(-2+5) * (x+5)

y-8=0

y=8 - This is the equation for the first 20 minutes of travel

Then, ferry turns due south (-2;8) and has a vertiacl line

The equation of verical line is x=a, so the equation will be x=2

b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat.

region looks like a circular disc with a center (-2;10)

(x+2)^2+(y-10)^2=3^2

(x+2)^2+(y-10)^2 <9 (interior of the circular disc)

(x+2)^2+(y-10)^2 >9 (exterior)

The equation of the line joining the Kingston and Edmonds is y=8

the point of intersection:

(x+2)^2+(8-10)^2=9

(x+2)^2=5

x is approximately 0.24; -4.24

(0.24;8) (-4.24;8) - intersection points

c) The ferry exits the radar during the trid due south long x=-2

The points of intersection of the circle and the line x=-2:

(-2+2)^2+(y-10)^2=9

0+(y-10)^2=0

y is 7.13

(-2;7)

d) Takes south turn at (-2;8), then ferry travels 0.8 miles up to point (-2;7) where it exists the radar zone

Speed is 9mph

The time taken to cover 1 mile = t=1/9hr=1/9 *60=6.667min

So, it exists after 6.67 minutes

e) Ferry enters at (-4.24;8) and takes turn due to south at (-2;8)

The distance travelled is = [-4.24+2]=2.24 miles

The time taken to cover these miles is = t=2.24/9 *60=14.93 min

After turning to south ferry remains in radar for 6.7 min

So, it remains in radar zone for 14.93+6.7=21.63min

8 0
2 years ago
Express 3/4 in sixty-fourths
vesna_86 [32]
It would be 48/64 this is done by finding how many times 4 fits in 64 (64/4) then multiplying 3 by that answer
7 0
2 years ago
Read 2 more answers
An online application charges $1.25 to download a song and $10.99 membership fee. Write an expression that gives the total cost
irina1246 [14]

Answer:

$18.49

Step-by-step explanation:

10.99+(1.25x6)

7 0
2 years ago
Read 2 more answers
Juana compró una camioneta 4x4 a S/ 42 000; además, sabe que la camioneta se depreciará (bajará su precio) en forma lineal duran
prohojiy [21]

Answer:

Una relación lineal es de la forma:

y = a*x + b.

donde a es la pendiente y b es la ordenada al origen.

en este caso, y es el precio de la camioneta, x es el numero de años que pasaron, a es la razon de depreciación de la camioneta y b es el precio inicial de la camioneta, b = $42,000.

Sabemos que después de 5 años, el precio de la camioneta es 21,000, entonces podemos resolver:

$21,000 = a*5 + $42,000

a*5 = $21,000 - $42,000 = -$21,000

a = -$21,000/5 = -$4,200

Esto significa que el precio decae $4,200 por año

4 0
2 years ago
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