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1 year ago

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Point T, the midpoint of segment RS, can be found using the formulas x = (6 – 2) + 2 and y = (4 – 6) + 6. What are the coordinat

es of point T? T(3, 2) T(3, 4) T(4, 5) T(4, 7)

2 answers:

Fiesta28 [93]1 year ago

5 0

Question:

Point T, the midpoint of segment RS, can be found using the formulas x = (1/2) (6 – 2) + 2 and y = (1/2) (4 – 6) + 6. What are the coordinates of point T?

Answer:

$T(4,5)$

Step-by-step explanation:

Given

$x = \frac{1}{2}(6 - 2) + 2$

$y = \frac{1}{2}(4 - 6) + 6$

Required

Determine the coordinates of T

The coordinates of T can be represented as $T(x,y)$

To do this, we simply solve for x and y

$x = \frac{1}{2}(6 - 2) + 2$

Solve 6 - 2

$x = \frac{1}{2}*4 + 2$

Solve 1/2 * 4

$x = 2 + 2$

$x = 4$

$y = \frac{1}{2}(4 - 6) + 6$

Solve 4 - 6

$y = \frac{1}{2}*-2 + 6$

Solve 1/2 * -2

$y = -1 + 6$

$y = 5$

Hence, the coordinates of T(x,y) is:

$T(x,y) = T(4,5)$

ozzi1 year ago

5 0

Answer:

C

Step-by-step explanation:

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stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number

Answer:

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Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

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square of a number decreased by 3 times the number = 28

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$\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}$

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