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2 years ago

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Anne states that reflections preserve side lengths, so PN 2 PN. PM apo, and MNON, therefore the triangles are congruent.

2 answers:

sukhopar [10]2 years ago

8 0

Answer:Only Anne

Step-by-step explanation:

Neporo4naja [7]2 years ago

7 0

Answer:

Only Anne

Step-by-step explanation:

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A gardener brought 5 rabbits, after 2 months rabbits became 10, and after 4 months they became 20. If the growth continues on th

kramer

Answer:

Initial population of Rabbit = 5 rabbit

After 2 months

Population of Rabbit = 10

After 4 months

population of rabbit = 20

Formula for growth is :

G = $G_{0}[1 + R]^n$ , where G is final population and $G_{0}$ is initial population, and R is growth rate.

1. 10 = 5 [1 +R]²

Dividing both sides by 5 , we get

2 = (1 + R)²

→ R + 1 = √2 ⇒ taking positive root of 2

→R = √2 -1

Amount of rabbit after 1 year = $20(1 + \sqrt2 -1)^8= 20 \times (\sqrt2)^8= 20 \times 2^4= 20 \times 16= 320$

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2 years ago

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If you know that a < b, and both a and b are positive numbers, then what must be true about the relationship between the oppo

nlexa [21]

What ever number A is, it is going to be less than whatever number B is.

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2 years ago

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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

5 0

2 years ago

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A. The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

erastovalidia [21]

Answer:

The average yearly salary of the architect is <u>$62,000</u> and the lawyer is <u>$100,000</u>.

Step-by-step explanation:

Given:

The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

Combined, an architect and a lawyer earn $ 210 thousand.

Now, to find the average yearly salary of an architect and a lawyer.

Let the average yearly salary of an architect be $x.$

So, the average yearly salary of the lawyer = $2x-24,000.$

Combined, architect and lawyer earn = $\$210,000.$

Now, to get the average salary of the architect and lawyer:

$x+(2x-24000)=210000$

$x+2x-24000=210000\\\\3x-24000=210000$

<em>Adding both sides 24000 we get:</em>

$3x=186,000\\\\Dividing\ both\ sides\ by\ 3\ we\ get:\\\\x=62000.$

<u>The average salary of architect = $62,000.</u>

Now, to get the average salary of lawyer by substituting the value of $x$ :

$2x-24000\\\\=2(62000)-24000\\\\=124000-24000\\\\=\$100,000.$

<u>The average salary of lawyer = $100,000.</u>

Therefore, the average yearly salary of the architect is $62,000 and the lawyer is $100,000.

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2 years ago

Leo is testing different types of greenhouse material to determine which type is most effective for growing strawberry bushes. H

alexandr1967 [171]

Answer:

Hey there!

This is not a valid experiment because the sunshine each section received were not equal.

Let me know if this helps :)

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2 years ago

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