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Virty [35]
2 years ago
12

An airplane started at point X, traveled 320 miles to point Y, adjusted its route, and traveled another 400 miles to point Z. If

the airplane is currently 599 miles from its starting position at point X, by how many degrees did it adjust its route at point Y?
Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
4 0

Answer:

67.88°

Step-by-step explanation:

If three sides of a triangle are known and you want to determine one angle, this can be done using cosine rule.

Given sides x, y, and z and the angle Y is opposite to side y, the cosine formula is given as:

y² = x² + z² - 2xzcosY

For this problem, x = 400 miles, y = 599 miles, z = 320 miles.

Using the cosine formula:

y^2=x^2+z^2-2xzcos(Y)\\Substituting:\\599^2=400^2+320^2-2(400)(320)cos(Y)\\2(400)(320)cos(Y)=400^2+320^2-599^2\\256000cos(Y)=-96401\\cos(Y)=-0.3766\\Y=cos^{-1}(-0.3766)\\Y=112.12^0

Degree to adjust its route at point Y = 180° - 112.12° = 67.88°

It needs to adjust by 67.88° at point Y

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Which algebraic expression represents the phrase "seven more than half of a number"?
Vika [28.1K]

Answer:

1/2x +7

Step-by-step explanation:

Let the unknown number be x

We want 1/2 of the number

1/2x

Then 7 more than  (add)

1/2x +7

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2 years ago
a flower garden is in the shape of a right triangle. The longest side of the triangle measures 13 meters. One of the shorter sid
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The answer is 10.4 Hope this helps
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2 years ago
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adam invests $6,139 in an retirement account with a fixed annual interest rate compounded continuously. after 17 years the balan
Digiron [165]

2485.97 would be what he earned as an interest rate. The percentage would be6%

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2 years ago
Consider the following equation. 3x4 − 8x3 + 6 = 0, [2, 3] (a) Explain how we know that the given equation must have a root in t
N76 [4]

Answer:

a) see your problem statement for the explanation

b) 2.54539334183

Step-by-step explanation:

(b) Many graphing calculators have a derivative function that lets you define the Newton's Method iterator as a function. That iterator is ...

  x' = x - f(x)/f'(x)

where x' is the next "guess" and f'(x) is the derivative of f(x). In the attached, we use g(x) instead of x' for the iterated value.

Here, our f(x) is ...

  f(x) = 3x^4 -8x^3 +6

An expression for f'(x) is

  f'(x) = 12x^3 -24x^2

but we don't need to know that when we use the calculator's derivative function.

When we start with x=2.545 from the point displayed on the graph, the iteration function g(x) in the attached immediately shows the next decimal digits to be 393. Thus, after 1 iteration starting with 4 significant digits, we have a result good to the desired 6 significant digits: 2.545393. (The interactive nature of this calculator means we can copy additional digits from the iterated value to g(x) until the iterated value changes no more. We have shown that the iterator output is equal to the iterator input, but we get the same output for only 7 significant digits of input.)

___

<em>Alternate iterator function</em>

If we were calculating the iterated value by hand, we might want to write the iterator as a rational function in Horner form.

  g(x) = x - (3x^4 -8x^3 +6)/(12x^3 -24x^2) = (9x^4 -16x^3 -6)/(12x^3 -24x^2)

  g(x) = ((9x -16)x^3 -6)/((12x -24)x^2) . . . . iterator suitable for hand calculation

3 0
2 years ago
Rework problem 9 from section 3.2 of your text, involving independent and disjoint events. For this problem, assume that Pr[A∪B]
tatuchka [14]

Two events are said to be  Disjoint or Mutually Exclusive if the two events can not  happen at the same time.For example when we throw a die getting an even number is disjoint to getting an odd number.

I.e Probability(A∩B)=0

Let me explain this concept through venn diagram.

Pr[A∪B]=0.7, Pr[A]=0.25

Since events are Disjoint

Pr[A∩B]=0

Pr[A∪B]=Pr[A] + Pr[B]

0.7=0.25 +Pr[B]

0.7-0.25=Pr[B]

⇒Pr[B]=0.45=45/100=9/20

Now events are said to be independent if Pr[A and B]=Pr[A] ×Pr[B]

Events are said to be independent if occurrence of one is not affected by occurrence of other.For example getting multiple of 2 as one event and getting multiple of 3 as second event when we throw a die.

Pr[A∪B]=0.7, Pr[A]=0.25

Pr[A∪B]= Pr[A]+ Pr[B]-Pr[A∩B]

But Pr[A∩B]= Pr[A] ×Pr[B]

⇒Pr[A∪B]= Pr[A]+ Pr[B]- Pr[A] ×Pr[B]

⇒0.7=0.25+p-0.25×p

⇒0.7-0.25=p- 0.25 p

⇒0.45=0.75 p

⇒p= 0.45/0.75

⇒p =3/5


5 0
2 years ago
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