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VMariaS [17]
2 years ago
5

adam invests $6,139 in an retirement account with a fixed annual interest rate compounded continuously. after 17 years the balan

ce reaches $8,624.97. what is the interest rate of the account ?
Mathematics
1 answer:
Digiron [165]2 years ago
8 0

2485.97 would be what he earned as an interest rate. The percentage would be6%

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Raphael graphed the system of equations shown. y = – 3 y = x – 0.8 What is the best approximation for the solution to this syste
Ber [7]
Given ---›

y = -3

&

y = x - 0.8

So,
=> x = y + 0.8

=> x = -3 + 0.8

=> x = -2.2

Therefore, the best approximation for the solution to this system of equations is = (–2.2, –3)
3 0
2 years ago
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Bridgette opened a store credit card to purchase a business suit for $463. She put the entire purchase on the credit card. Her A
irinina [24]
Begin by computing the <span>monthly interest rate like this:
</span>\frac{14.99}{12}=1.25
<span>Each month, we have to substract from $463 the monthly rate and the payment of 5%, which result in the following formula:
</span>463(1-(0.05+0.0125))^3=463\times0,9375^3\\=381.5
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So, after three months, it ill remains $381.5 in </span><span>Bridgette account. </span>
5 0
2 years ago
Write the number 1.8 in the form a/b, using integers, to show that it is a rational number.
Pepsi [2]

1. Note that the number 1.8 consists of two parts 1 and 0.8.

2. The decimal 0.8 can be written as the fraction \dfrac{8}{10}.

3. Add these two numbers:

1+\dfrac{8}{10}=\dfrac{10}{10}+\dfrac{8}{10}=\dfrac{10+8}{10}=\dfrac{18}{10}.

4. Since 18=2·3·3 and 10=2·5, the fraction \dfrac{18}{10} can be simplified to the rational number

\dfrac{18}{10}=\dfrac{2\cdot 3\cdot 3}{2\cdot 5}=\dfrac{3\cdot 3}{5}=\dfrac{9}{5}.

3 0
2 years ago
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A number, x, rounded to 2 significant figures is 1300<br>Write down the error interval for x.​
nikitadnepr [17]

Answer:

[1250,1350).

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

It is possible if,

1. The value of x is greater than of equal to 1250 and less than or equal to 1300.

i.e., 1250\leq x\leq 1300     ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

i.e., 1300\leq x       ...(2)

On combining (1) and (2), we get

1250\leq x < 1350

1350 is not included in the error interval for x.​

Interval notation is [1250,1350).

Therefore, the error interval for x is [1250,1350).

7 0
2 years ago
On January 1, year 1, Klondike issued 10-year bonds with a stated rate of 10% and a face amount of $100,000. The bonds pay inter
Nataliya [291]

Answer:

91,000

Step-by-step explanation:

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