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2 years ago

Choose the abbreviation of the postulate or theorem that supports the conclusion that △WAS ≅ △NOT.

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

Answer: SSS

Step-by-step explanation:

WA = NO

AS = OT

SW = TN

△WAS ≅ △NOT by SSS Congruency Theorem

snow_tiger [21]2 years ago

4 0

Answer: SSS

Step-by-step explanation:

Given: In ΔWAS and ΔNOT

WA = NO, AS = OT, SW = TN

By SSS congruence postulate , we have

ΔWAS ≅ ΔNOT

The SSS congruence postulate or side-side-side postulate tells that if all the three sides of a triangle is equal to all the corresponding sides of the other triangle, then both the triangles are congruent.

Hence, SSS is the right abbreviation used for "side-side-side postulate."

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During the 2008-2009 financial crisis, the GDP of the USA reduced from $14.72 trillion in 2008 to$14.42 trillion in 2009. What i

Bad White [126]

Answer:

2.04

Step-by-step explanation:

The GDP of USA IN 2008 = $14.72 trillion

The GDP of USA IN 2009 = $14.42 trillion

Change in GDP

$14.72 trillion- $14.42 trillion = $0.3 trillion

Percentage Change

($0.3 trillion/$14.72 trillion) x 100%

0.02038 X 100% = 2.038=2.04 approximately

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2 years ago

The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin

tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950 $e^{0.45t}$

a) rate of growth is

Bacteria growth model N(t) = no $e^{rt}$

Where r is the growth rate

hence r = 0.45

= 45%

b) Initial population of culture at t = 0

n(0) = 950 $e^{0.45(0)}$

= 950 $e^{0}$

= 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) = 950 $e^{0.45(5)}$

= 950 $e^{2.25}$

= 9013.35

= 9013 bacteria

6 0

2 years ago

On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number

Alina [70]

<h3>Question:</h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3>Answer:</h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3>Solution:</h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

Given items were sold for $356

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

$c \times 8 + p \times 10 = 356$

8c + 10p = 356 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

p = 40 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

Substitute c = 22 in eqn 3

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0

2 years ago

Which polynomial function has a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1?

svlad2 [7]

Answer:

C. $f(x)=(x-(7-i))(x-(5+i))(x-(7+i))(x-(5-i))$

Step-by-step explanation:

We want to find the equation of a polynomial the following properties;

i. Leading coefficient is 1

ii. roots (7 + i) and (5 – i) with multiplicity 1

Recall the complex conjugate properties of the roots of a polynomial.

According to this property, if

$a+bi$ is a root of a polynomial, then the complex conjugate, $a-bi$ is also a root.

This means that:

(7 - i) and (5 + i) with multiplicity 1 are also roots of this polynomial.

The complete set of roots are:

$x=(7+i),x=(7-i),x=(5-i),x=(5+i)$

Therefore the polynomial is:

$f(x)=(x-(7-i))(x-(5+i))(x-(7+i))(x-(5-i))$

The correct choice is C.

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