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gregori [183]
1 year ago
12

In one of its Spring catalogs, L.L. Bean® advertised footwear on 28 of its 192 catalog pages. Suppose we randomly survey 20 page

s. We are interested in the number of pages that advertise footwear. Each page may be picked more than once. Part (a) In words, define the random variable X. the number of pages in the catalog the number of pages we must survey until we find one that advertises footwear the number of pages that advertise footwear the number of footwear styles the number of times a page could be picked Part (b) List the values that X may take on. X = 0, 1, 2, ..., 192 X = 1, 2, ..., 28 X = 1, 2, ..., 20 X = 0, 1, 2, ..., 20 X = 0, 1, 2, ..., 28 Part (c) Give the distribution of X. (Enter exact numbers as integers, fractions, or decimals.) X ~ ? , Part (d) How many pages do you expect to advertise footwear on them? (Round your answer to the nearest whole number.) 3 Part (e) Is it probable that all twenty will advertise footwear on them? Why or why not? (Round your answer to two decimal places.) No , because the probability that all twenty will advertise footwear is . Part (f) What is the probability that fewer than eight will advertise footwear on them? (Round your answer to four decimal places.) Part (g) Reminder: A page may be picked more than once. We are interested in the number of pages that we must randomly survey until we find one that has footwear advertised on it. Define the random variable X. the number of pages in the catalog the number of pages we must survey until we find one that advertises footwear the number of pages that advertise footwear the number of footwear styles the number of times a page could be picked Give its distribution. (Enter an exact number as an integer, fraction, or decimal.) X ~ ? Part (h) What is the probability that you only need to survey at most five pages in order to find one that advertises footwear on it? (Round your answer to four decimal places.) Part (i) How many pages do you expect to need to survey in order to find one th
Mathematics
1 answer:
vichka [17]1 year ago
8 0
100 easy os it correct
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if you are adding two fractions that are both greater than 1/2 what must be true about the sum? Give three examples to support y
Sunny_sXe [5.5K]

Answer:

If you are adding to fractions that are both greater than 1/2, the sum will be greater than 1.

Step-by-step explanation: 1/2 + 1/2 =1    

Since both fractions are greater, obviously the sum will too.

Examples: 2/3+3/4= 1 5/12        4/6+6/9= 1 1/3

Hope this helps

6 0
2 years ago
A copper smelting process is supposed to reduce the arsenic content of the copper to less than 1000 ppm. let μ denote the mean a
Hitman42 [59]
The rejection region is give by 

|z_{test}|\ \textgreater \ z_{\alpha/2}

where the test statistics is given by

\frac{\bar{x}-\mu}{\sigma/\sqrt{n}} = \frac{980-1000}{100/\sqrt{75}} \\ \\ = \frac{-20}{100/8.6603} = \frac{-20}{11.5470} =-1.73

i.e. |z_{test}|=|-1.73|=1.73

Thus, z_{\alpha/2}=1.73

Using the statistical table, the level of the test is 0.04.
6 0
2 years ago
In ΔXYZ, x = 71 cm, y = 91 cm and z=71 cm. Find the area of ΔXYZ to the nearest square centimeter.
anyanavicka [17]

since its an isoscelies trangle, they probably wanted you to do base times height

make a 71-91/2-x x triangle

where x is the height of the triangle to the base 91 and 71 is the hypothenuse

and then do bh/2

or

use heron's formula

s= 71+91/2

area= \sqrt{(71+91/2)(71+91/2-71)(71+91/2-71)(71+91/2-91)}

have fun solving that

5 0
2 years ago
What is the volume, in cubic in, of a cylinder with a height of 12in and a base radius of 6in, to the nearest tenths place?
Shtirlitz [24]

Answer:

1356.5 cubic inches

Step-by-step explanation:

Given information:

Height of the cylinder = 12 in.

Radius of base of the cylinder = 6 in.

We need to find volume of the cylinder.

Volume of cylinder:

V=\pi r^2h

where, r is the radius of base and h is height of the cylinder.

Substitute the given values in the above formula.

V=\pi (6)^2(12)

V=(3.14)(36)(12)            [\because \pi=3.14]

V=1356.48

Approx to nearest tenth.

V\approx 1356.5

Therefore, the volume of cylinder is 1356.5 cubic inches.

8 0
2 years ago
A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports
hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

t  =  3.054

4

The p-value  is   p-value  =  P(Z >  3.054) = 0.0011291

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1  =  51

    The first sample  mean is \mu_1  =  36

    The second sample size is  n_2  =  41

    The second sample  size is  \mu_2  =  25

     The first standard deviation is  \sigma _1  =  21.4 \  g

    The second standard deviation is  \sigma _2  =  12.8 \  g

  The  level of significance is  \alpha =  0.05

The  null hypothesis is  H_o  :  \mu_1 = \mu_ 2

The  alternative hypothesis is  H_a :  \mu_1 > \mu_2

Generally the test statistics is mathematically represented as

    t  =  \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1}  + \frac{s_2^2}{n_2}  } }

=>   t  =  \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51}  + \frac{ 12.8^2}{41}  } }

=> t  =  3.054

The  p-value is mathematically represented as

     p-value  =  P(Z >  3.054)

Generally from the z table  

             P(Z >  3.054) =  0.0011291

=>   p-value  =  P(Z >  3.054) = 0.0011291

From the values obtained  we see that p-value  < \alpha so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0
2 years ago
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