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MariettaO [177]

2 years ago

12

Circle R is shown. Tangents F G and H G intersect at point G outside of the circle to form an angle with a measure of 50 degrees

. Point E is on the second arc. Arc F H has a measure of x degrees. In the diagram of circle R, m∠FGH is 50°. What is mAngle F E H? 130° 230° 260° 310°

2 answers:

Rus_ich [418]2 years ago

8 0

Answer:

B 230

Step-by-step explanation:

vodka [1.7K]2 years ago

4 0

Answer:

if x = arc FG, then x = 130 degrees, the bigger arc is 230 degrees.

Step-by-step explanation:

We see there are 2 tangent lines of circle R

There is a theorem that says angle FGH = [ (arc FEH) - (arc (FH)] /2

50 = (arc FEH - arc FH) /2

arc FEH - arc FH = 100

and arc FEH + arc FH = 360

solving this system you should get FH = 130 and FEH = 230

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The actual proportion of voters who plan to vote for a particular proposition in the next election is 70%, but LaShandra does no

Setler [38]

Answer:

0.0417

Step-by-step explanation:

Given the following;

p = 0.7, n=121

The sampling distribution of sample proportion will be approximately normal with mean

\mu_{\hat{p}}=p=0.7

and standard deviation

\sigma_{\hat{p}}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7\cdot 0.2}{121}}=0.0417

Check attachment for the curve diagram.

4 0

2 years ago

A circle with radius of \greenD{6\,\text{cm}}6cmstart color #1fab54, 6, start text, c, m, end text, end color #1fab54 sits insid

Diano4ka-milaya [45]

Answer: $141 cm^{2}$

Step-by-step explanation:

We have two circles:

Cirlce 1, with a radius $r=6 cm$ and area $A_{1}$ :

$A_{1}=\pi r^{2}$

And Cicle 2, with a radius $R=9 cm$ and area $A_{2}$ :

$A_{1}=\pi R^{2}$

Since Circle 1 is inside Circle 2 and assuming the area of the shaded region is the shown in the attached image, its area is:

$A=A_{2}-A_{1}=\pi R^{2}-\pi r^{2}$

$A=\pi (R^{2}- r^{2})$

$A=\pi ((9cm)^{2}- (6cm)^{2})$

Finally:

$A=141.37 cm^{2} \approx 141 cm^{2}$

3 0

2 years ago

Which of the following represents the zeros of f(x) = 5x3 − 6x2 − 59x + 12? (2 points)

Furkat [3]

Answer:

4, −3, 1 over 5

Step-by-step explanation:

x is a zero of $f(x)$ if $f(x) = 0$

In this problem, we have that:

$f(x) = 5x^{3} - 6x^{2} - 59x + 12$

4, 3, 1 over 5

$f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0$

So 4 is a zero of the function

$f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84$

So 3 is not a zero of the function, and this option is incorrect

4, 3, − 1 over 5

$f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84$

So 3 is not a zero of the function, and this option is incorrect

4, −3, 1 over 5

$f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0$

So 4 is a zero of the function

$f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0$

So -3 is a zero of the function

$f(\frac{1}{5}) = f(0.2) = 5*(0.2)^{3} - 6*(0.2)^{2} - 59*(0.2) + 12 = 0$

So 1 over 5 is a zero of the function

This is the correct answer.

4, −3, −1 over 5

$f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0$

So 4 is a zero of the function

$f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0$

So -3 is a zero of the function

$f(-\frac{1}{5}) = f(-0.2) = 5*(-0.2)^{3} - 6*(-0.2)^{2} - 59*(-0.2) + 12 = 23.52$

-1 over 5 is not a zero of the function

5 0

2 years ago

A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost

iris [78.8K]

Answer:

The venue has to host 47 events throughout the year

Step-by-step explanation:

Profit:

Profit is revenue subtracted by costs.

Per event:

$100,000 revenue

$50,000 costs

$100,000 - $50,000 = $50,000 profit.

If the venue wants to make a total profit margin of $2,350,000, how many events does the venue have to host throughout the year?

1 event - $50,000 profit.

x events - $2,350,000 profit.

$50000x = 2350000$

$x = \frac{2350000}{50000}$

$x = 47$

The venue has to host 47 events throughout the year

6 0

2 years ago

An experiment consists of determining the speed of automobiles on a highway by the use of radar equipment. The random variable i

jek_recluse [69]

Answer:

Option b. continuous random variable

Step-by-step explanation:

An experiment consists of determining the speed of automobiles on a highway by the use of radar equipment.

In this experiment the speed is the the random variable.

Now, speed can take any value within an interval.

It can take infinite values within an interval.

Also, speed is always measured and not counted.

Thus, speed is a continuous random variable.

Thus, the correct answer is

Option b) continuous random variable

6 0

2 years ago

Read 2 more answers