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Sindrei [870]
2 years ago
7

Your friend is trying to grow her hair as long as her cousin’s hair. The table shows their hair lengths y (in inches) in differe

nt months x. Month Friends Hair(in) Cousins Hair(in) 3 4 7 8 6.5 9. solve for the cousins hair.
Mathematics
1 answer:
Effectus [21]2 years ago
7 0
<span>Given the table that shows the hair lengths y (in inches) of your friend and her cousin in different months x.

Month      Friends Hair(in)      Cousins Hair(in)
    3                     4                              7
    8                    6.5                            9.

To solve for the cousins hair, recall that the equation of a line is given by

y = mx + c

From the table,

7 = 3m + c . . . (1)
9 = 8m + c . . . (2)

(1) - (2) ⇒ -2 = -5m
\Rightarrow m= \frac{2}{5} =0.4

Substituting for m into equation (1) gives:

7=3(0.4)+c \\  \\ \Rightarrow c=7-1.2=5.8

Therefore, the equation representing the growth of the cousin's hair is given by y = 1.2x + 5.8
</span>
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Answer:

\frac{3}{20}

Step-by-step explanation:

Fraction of the total that is for corn (TC - Total corn):

TC=\frac{1}{4}

fraction of the corn section that is for white corn (WC - white corn in the corn seccion):

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we need to find the fraction of the whole field that is for the white corn.

For this we need to find how much is \frac{3}{5} out of the \frac{1}{4} destinated to corn, and this will be the fraction of the total that is for white corn. We find this fraction by multiplying the fraction of corn (\frac{1}{4}) by the fraction of white corn in the corn section (\frac{3}{5}).

I will call the total fraction of white corn TWC, thus:

TWC=WC*TC=\\=\frac{3}{5} *\frac{1}{4} \\\\=\frac{3*1}{5*4} \\\\=\frac{3}{20}

the answer is: \frac{3}{20} of the whole field is planted with white corn

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The distance between place A and place B is 60 miles. the distance from place A to place C is 15% of the distance from place A t
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C. Phonograph were inferior in sound quality.

Step-by-step explanation:

Researches have shown that plants respond to the sounds of their pollinator.

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Greater the intensity of the sound of the pollinator, the faster the reaction will be.

Phonographs have a sound of lower intensity when compared to the intensity of sound produced by the radio.

Thus the radio was better than the phonograph in encouraging the concept of cross-pollination.

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