What is the operation used for the following terms: times, product, twice, etc.

Jason Witten's Salary Negotiation Let's say that tight end Jason Witten (a football player) was given two options when negotiati

Leokris [45]

Answer:

Option 1: It is better for him to be paid per catch, starting with 1 cent and doubling with each catch up to 110

Explanation:

If Jason were to be paid per catch given that he makes a total of 110 catches for the 2017 season in his new contract, he would make a total of :

0.01 × 2^109 = $6.4903711e+30(calculator result, means 6 then 30 digits after)

Therefore it is better for Jason to be paid per catch and not a flat fee of $2000000

3 0

1 year ago

The results of a race car are shown. Determine who drove the fastest. Explain.

monitta

We have to calculate speed for 1 lap for all of 'em.

Cutwright - 84/35 = 2.4 mins for 1 lap

Evans- 96.6/42 = 2.3 mins for 1 lap

Liza- 102.6/38 = 2.7 mins for 1 lap

So, EVANS drove fastest among them as he took less time...

8 0

1 year ago

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A circle with radius of \greenD{4\,\text{cm}}4cmstart color #1fab54, 4, start text, c, m, end text, end color #1fab54 sits insid

mario62 [17]

Answer:

The area of the shaded region is $329.87\ cm^2$

Step-by-step explanation:

<u><em>The correct question is</em></u>

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

To find out the shaded region subtract the area of the smaller circle from the area of the larger circle

so

$A=\pi r_a^{2} -\pi r_b^{2}$

simplify

$A=\pi (r_a^{2} -r_b^{2})$

where

r_a is the radius of the larger circle

r_b is the radius of the smaller circle

we have

$r_a=11\ cm\\r_b=4\ cm$

substitute

$A=\pi (11^{2} -4^{2})$

$A=\pi (105)\ cm^2$

assume

$\pi=3.1416$

substitute

$A=(3.1416)(105)=329.87\ cm^2$

7 0

2 years ago

Match the following guess solutions ypyp for the method of undetermined coefficients with the second-order nonhomogeneous linear

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

1 ) Given that

$(d^2y/dx^2) + 4y = x - x^2 + 20\\\\ (d^2y/dx^2) + 4y = - x^2 + x + 20$

For a non homogeneous part $- x^2 + x + 20$ , we assume the particular solution is

$y_p(x) = Ax^2 + Bx + C$

2 ) Given that

$d^2y/dx^2 + 6dy/dx + 8y = e^{2x}$

For a non homogeneous part $e^{2x}$ , we assume the particular solution is

$y_p(x) = Ae^{2x}$

3 ) Given that

y′′ + 4y′ + 20y = −3sin(2x)

For a non homogeneous part −3sin(2x) , we assume the particular solution is

$y_p(x) = Acos(2x)+Bsin(2x)$

4 ) Given that

y′′ − 2y′ − 15y = 3xcos(2x)

For a non homogeneous part 3xcos(2x) , we assume the particular solution is

$y_p(x) = (Ax+B)cos2x+(Cx+D)sin2x$

4 0

1 year ago

Solve the following quadratic equations by extracting square roots.Answer the questions that follow.

Vikentia [17]

Answer:

1. x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

Taking square root on both sides

$\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\$

x=±4

2. t^2=81

Taking square root on both sides

$\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}$

t=±9

3. r^2-100=0

$r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}$

r=±10

4. x²-144=0

x²=144

Taking square root on both sides

$\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}$

x=±12

5. 2s²=50

$\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}$

s=±5 ..

4 0

1 year ago

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