The decay rate should have units, it should be negative and it should be 100 times smaller than what you posted.
k = -.000124 / years
k = -.000124 / years
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.000124
Half-Life =
<span>
<span>
<span>
5589.8951612903
</span>
</span>
</span>
Half-Life =
5,590 (rounded)
elapsed time = half-life * log(bgng amt / end amt) / log(2)
elapsed time = 5,590 * log(10) /
<span>
<span>
<span>
0.3010299957
</span>
</span>
</span>
elapsed time = 5,590 * 1 / <span>
<span>
0.3010299957
</span>
</span>elapsed time =
<span>
<span>
<span>
18,569 years
</span></span></span>Source:
http://www.1728.org/halflife.htm
Answer:
18:162
Step-by-step explanation:
1:9
1+9=10
(1×180)÷10= 18
(9×180)÷10=162
During her pre-college years, Elise won 30% of the swim races she entered. During college, Elise won 20% of the swim races she entered. We can conclude that, in high school and college combined, Elise won <span>more than 20% but less than 30% of the races she entered</span>
2x+4x-4=2+4x
2x+4x-4x=2+4
2x=6
x=3
25-x=15-3x-10
3x-x= 15-10-25
2x= -20
x= -10
4x=2x+2x+5x-5x
2x+2x+5x-5x-4x
0 . no solution
Answer:
1. Multiply (2) by 2 to eliminate the x-terms when adding
2. Multiply (2) by 3 to eliminate the y- term
Step-by-step explanation:
Use this system of equations to answer the questions that follow.
4x-9y = 7
-2x+ 3y= 4
what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?
4x-9y = 7 (1)
-2x+ 3y= 4 (2)
Multiply (2) by 2 to eliminate the x-terms when adding the first equation
4x-9y = 7
-4x +6y = 8
Adding the equations
4x + (-4x) -9y + 6y = 7 + 8
4x - 4x - 3y = 15
-3y = 15
y = 15/-3
= -5
what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?
4x-9y = 7 (1)
-2x+ 3y= 4 (2)
Multiply (2) by 3 to eliminate the y- term
4x - 9y = 7
-6x + 9y = 12
Adding the equations
4x + (-6x) -9y + 9y = 7 + 12
4x - 6x = 19
-2x = 19
x = 19/-2
= -9.5
x = -9.5
