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Doss [256]
2 years ago
5

Sommer bought a baseball card for x dollars. Later, she sold it for 1.4x dollars. Which is another way to describe the change in

the price of the baseball card?
A. $0.04 increase
B. $0.40 increase
C. 4% increase
D. 40% increase
Mathematics
1 answer:
svp [43]2 years ago
4 0
Answer is D. 40% increase.
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Danika concludes that the following functions are inverses of each other because f(g(x)) = x. Do you agree with Danika? Explain
nordsb [41]
I hope this helps you..;

6 0
2 years ago
Read 2 more answers
A 4/7 inch pipe is to be shortened to 3/8 inch. How much must be removed?
11Alexandr11 [23.1K]

11/56 inches or 0.196 inches must be removed.

The pipe measures 4/7 inches but needs to be reduced to 3/8 inches.

In order to find out the inches to be removed, you must subtract the length that the pipe should be from the length that it currently is.

<em>Length to be removed = 4/7 - 3/8</em>

You need a common denominator so find the lowest common factor of both denominators:

= 56

In the shared fraction, multiply the numerator by the number you get when you divide 56 by the denominator.

= 56/7 = 8                                      8 x 4 = 32

= 56 / 8 = 7                                    7 x 3 = 21

= (32 - 21) / 56

= 11 / 56 inches

= 0.196 inches

In conclusion, 11/56 inches must be removed to get the pipe to 3/8 inches

<em>Find out more at brainly.com/question/4681199.</em>

6 0
1 year ago
The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin
Free_Kalibri [48]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.03

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03  

= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03  

=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12  

Thus, 8.17 g separates the top 3% of the weights.

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90  

Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

7 0
2 years ago
PART A: Marvin has a coupon the discount is the rental of a full-size car by $25 they decide to buy insurance for each day if th
natita [175]

Answer:

i dont know about the other parts but part A is 19

Step-by-step explanation:

6 0
2 years ago
Define four symbolic constants that represent integer 25 in decimal, binary, octal, and hexadecimal formats
stealth61 [152]

Answer:

1) Decimal    25= (25)_{10}

2) Binary    25= (11001)_2

3) Octal   25= (31)_8

4) Hexadecimal   25= (19)_{16}

Step-by-step explanation:

Given : Integer is 25                      

To find : Represent integer in decimal, binary, octal, and hexadecimal formats.

Solution :

1) Integer into decimal - To convert into decimal the base goes to 10.

So, 25= (25)_{10}

2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.

Divide 25 by 2 and note down the remainders.

2 | 25

2 | 12    R=1    ←

2 | 6     R=0   ↑

2 | 3      R=0  ↑

2 | 1  →   R=1   ↑

So,   25= (11001)_2

3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.

Divide 25 by 8 and note down the remainders.

8 | 25

  | 3 →   R=1    

So,   25= (31)_8

4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.

Divide 25 by 16 and note down the remainders.

16 | 25

   | 1 →   R=9    

So,   25= (19)_{16}

3 0
2 years ago
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