Question

The length of a rectangle is 24 units. can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)

Answer 1

Okay, well we start out with the equation P=66, where P is perimeter. You should create equations using variables to explain each piece of information you are given. Follow the equations below and see if you can understand how to do another one like this. In this problem, l is length and w is width.

P = 66                               The perimeter is equal to 66

l = 3 + w                           The length of one side is 3 more than the width

2l + 2w = 66                      A rectangle's perimeter is calculated by adding the lengths and widths

2(3 + w) + 2w = 66           Use what you know about length from step 2 to replace the variable in step 3

6 + 2w + 2w = 66              Multiply

6 + 4w = 66                       Add like terms

4w = 60                            Subtract

w = 15                             Divide

l = 3 + w                         Remember step 2?

l = 3 + 15                       Replace the variable using your value for w

l = 18                             Add

And you're done! Always check your work. It helps to create a picture of a rectangle while you're doing these problems as well. As you get used to these problems more and more, you can show more or less work than I've shown, but try to stay true to what the teacher asks of you. Good luck!

Answer 2

No the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y. The correct option among all the options that are given in the question is the first option or option "A". The perimeter of the rectangle can be found by adding all four sides of the rectangle. I a rectangle the opposite sides are equal and so on adding we get
Perimeter (x) = 24 + 24 + 11 + 11 = 70. 
There is no chance that the perimeter of the given rectangle will be 60. SO yeah thats the Answer