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Natalija [7]
2 years ago
15

The sales manager of a company awarded a total of \$3000$3000 in bonuses to the most productive salespeople. The bonuses were aw

arded in amounts of \$250$250 or \$750$750. If at least one \$250$250 bonus and at least one \$750$750 bonus were awarded, what is one possible number of \$250$250 bonuses awarded?
Mathematics
1 answer:
alisha [4.7K]2 years ago
4 0

Answer:

one possible number of bonus is 9.

Step-by-step explanation:

Let, the number of $250 bonus = x and number of $750 bonus = y.

We have that bonuses are given in amounts $250 and $750.

Since, the total bonus is $3000.

So, we get,

250x + 750y = 3000.

As, there is atleast one $250 bonus and atleast one $750 bonus.

Let, the minimum number of bonus of $750 be 1 i.e. y = 1.

Substitute in the equation gives,

250x + 750 × 1 = 3000

i.e. 250x = 3000 - 750

i.e. 250x = 2250

i.e. x = 9

Thus, the maximum number of $250 bonus are 9.

Hence, one possible number of bonus is 9.

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You know that the current exchange rate for US dollars (USD) to Indian rupees (INR) is 1:45.85, that the exchange rate for India
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Answer:

C

Step-by-step explanation:

the answer on edgeunity

3 0
2 years ago
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The areas of the squares created by the side lengths of the triangle are shown. Which best explains whether this triangle is a r
nikitadnepr [17]

Answer:

Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because 9+12\neq 15

Step-by-step explanation:

The complete question in the attached figure

we know that

If the length sides of a triangle, satisfy the Pythagorean Theorem, then is a right triangle

c^2=a^2+b^2

where

c is the hypotenuse (the greater side)

a and b are the legs

In this problem

The length sides squared of the triangle are equal to the areas of the squares

so

c^2=15\ in^2  

a^2=12\ in^2

b^2=9\ in^2

substitute

15=12+9

15=21 ----> is not true

so

The length sides not satisfy the Pythagorean Theorem

therefore

Based on the converse of the Pythagorean Theorem, the triangle is not a right triangle, because 9+12\neq 15

8 0
2 years ago
Read 2 more answers
Rewrite each expression as a product of two or quotient of two powers ​
Paul [167]

Answer:

The product is 5^{40}*3^{70}

Step-by-step explanation:

To do this we must understand how the basic operations apply to powers. If the power has the same base and we multiply them, the base remains the same while we sum the powers, if we divide them the base remains the same and we subtract the powers, if we try to make a power of a power the two powers multiply. Applying this rule we have:

(\frac{5^8*3^7}{5^4})^{10}\\(\frac{5^8}{5^4}*3^7)^{10}\\(5^4*3^7)^{10}\\5^{40}*3^{70}

6 0
2 years ago
Mai bought eleven 12-ounce bags of
ella [17]

Answer:

8.25 pounds

Step-by-step explanation:

When you multiply 12 and 11 you get 132. So then you would have to divided the total amount of ounces by 16 to get the amount of pounds

5 0
2 years ago
Given directed line segment QS , find the coordinates of R
Degger [83]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at (x_1,y_1) and B(x_2,y_2) is given by the formula:

x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1

If point Q is at (x_1,y_1) and S at (x_2,y_2)  and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1

Let us assume Q(−9,4) and S(7,−4)

x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1

4 0
2 years ago
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