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Natalija [7]
2 years ago
15

The sales manager of a company awarded a total of \$3000$3000 in bonuses to the most productive salespeople. The bonuses were aw

arded in amounts of \$250$250 or \$750$750. If at least one \$250$250 bonus and at least one \$750$750 bonus were awarded, what is one possible number of \$250$250 bonuses awarded?
Mathematics
1 answer:
alisha [4.7K]2 years ago
4 0

Answer:

one possible number of bonus is 9.

Step-by-step explanation:

Let, the number of $250 bonus = x and number of $750 bonus = y.

We have that bonuses are given in amounts $250 and $750.

Since, the total bonus is $3000.

So, we get,

250x + 750y = 3000.

As, there is atleast one $250 bonus and atleast one $750 bonus.

Let, the minimum number of bonus of $750 be 1 i.e. y = 1.

Substitute in the equation gives,

250x + 750 × 1 = 3000

i.e. 250x = 3000 - 750

i.e. 250x = 2250

i.e. x = 9

Thus, the maximum number of $250 bonus are 9.

Hence, one possible number of bonus is 9.

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Caroline, Colin & Sarah share some money.
aev [14]

Answer:

Colin gets  \frac{2}{3}

Step-by-step explanation:

One part is excluded in the problem. That part is:

"Caroline gets \frac{1}{9} of the money."

<u>Solution:</u>

If Caroline gets 1/9th, then remaining is:

1-\frac{1}{9}=\frac{8}{9}

Colin and Sarah share in ratio 3 is to 1, that means 3 + 1 = 4 parts...

8/9th in 4 parts means, each part is:

\frac{\frac{8}{9}}{4}=\frac{2}{9}

We know Colin gets "3" parts of the total, each part is (2/9)th, so 3 parts would be:

3*\frac{2}{9}=\frac{6}{9}=\frac{2}{3}

Colin gets  \frac{2}{3}

7 0
2 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 170 mg sample.(a) Find the mass that remains after t years.(b) How mu
saul85 [17]

Answer:

212.9 years

Step-by-step explanation:

Given that the half-life of cesium-137 is 30 years. Suppose we have a 170 mg sample

P0 = 175

P(30) = 87.5

So we can write equation as

P(t) = 170(\frac{1}{2} )^{\frac{t}{30} }

b) After 60 years t = 30

In 30 years it becomes half and hence in 60 years it would become 1/4

i.e. P(60) = 137(1/2^4) = 34.25 mg

c) If P(t) =1, let us find t

137(1/2)^{\frac{t}{30} } =1\\\\n = 7.098 years\\n = 7.1*30 = 212.9 years

212.9

5 0
2 years ago
Is y=x to the 2nd power + 6 linear on nonlinear and why?
Anna35 [415]
It is nonlinear because X is being raised to the second power
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