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Rom4ik [11]
1 year ago
7

Here is a picture that shows one side of a child's wooden block with a semicircle cut out at the bottom. What is the area of the

wooden block? *HINT (subtract the semi-circle from the rectangle)* The face of an arch-shaped block. The horizontal side of the block is labeled 9 centimeters and the vertical side of the block is labeled 4.5 centimeters. A semi circle with diameter labeled 5 centimeters is removed from the block.

Mathematics
1 answer:
ehidna [41]1 year ago
7 0

Answer:

30.7 cm² (nearest tenth)

Step-by-step explanation:

Area of the wooden block = area of rectangle - area of semi-circle

Area of Rectangle = length × width

Length = 9 cm

Width = 4.5 cm

Area of rectangle = 40.5 cm²

Area of semi-circle = ½(πr²)

Radius (r) = ½ of diameter = ½*5 = 2.5 cm

π = 3.14

Area of semi-circle = ½(3.14*2.5²)

Area of semi-circle = 9.8125 cm²

✅Area of the wooden block = 40.5 - 9.8125 = 30.7 cm² (nearest tenth)

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Ksju [112]

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Answer:

  96 cubic feet

Step-by-step explanation:

A volume that is 16 ft by 18 ft by 1/3 ft will be ...

  V = LWH

  V = (16 ft)(18 ft)(1/3 ft) = 96 ft³

96 cubic feet of concrete are needed.

7 0
2 years ago
Solve the inequality 47.75 + x Less-than-or-equal-to 50 to determine how much more weight can be added to Li's suitcase without
myrzilka [38]

Answer:

x is less-than-or-equal-to 2.25 (x ≤ 2.25)

Step-by-step explanation:

We can write down the inequality that represents the weight Li can add without going over the 50 pound limit:

47.75 + x ≤ 50

If we solve for x we have:

47.75 + x ≤ 50

x ≤ 50 - 47.75

x ≤ 2.25

Therefore, the weight Li can add to the suitcase is less-than-or-equal-to 2.25

6 0
1 year ago
Read 2 more answers
A large manufacturing plant has analyzed the amount of time required to produce an electrical part and determined that the times
WARRIOR [948]

Answer:

We conclude that the new procedure will not decrease the population mean amount of time required to produce the part.

Step-by-step explanation:

We are given that a large manufacturing plant has analyzed the amount of time required to produce an electrical part and determined that the times follow a normal distribution with mean time μ = 45 hours.

A random sample of 25 parts will be selected and the average amount of time required to produce them will be determined. The sample mean amount of time is = 43.118 hours with the sample standard deviation s = 5.5 hours

<em>Let </em>\mu<em> = population mean amount of time required to produce an electrical part using new procedure</em>

SO, <u>Null Hypothesis</u>, H_0 : \mu \geq  45 hours   {means that the new procedure will remain same or increase the population mean amount of time required to produce the part}

<u>Alternate Hypothesis,</u> H_a : \mu < 45 hours   {means that the new procedure will decrease the population mean amount of time required to produce the part}

The test statistics that will be used here is <u>One-sample t test statistics </u>because we don't know about the population standard deviation;

              T.S.  = \frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }  ~ t_n_-_1

where,  \mu = sample mean amount of time = 43.118 hours

             s = sample standard deviation = 5.5 hours

             n = sample of parts = 25

So, <u><em>test statistics</em></u>  =  \frac{43.118-45}{{\frac{5.5}{\sqrt{25} } } }  ~ t_2_4

                               =  -1.711

<em>Now at 0.025 significance level, the t table gives critical value of -2.064 at 24 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the new procedure will remain same or increase the population mean amount of time required to produce the part.

4 0
1 year ago
Tracie rides the bus home from school each day. The graph represents her distance from home relative to the number of minutes si
Semmy [17]

Step-by-step explanation:

Tracie’s bus travels towards her home at an average speed of StartFraction one-half EndFraction mile per minute.

4 0
1 year ago
Read 2 more answers
Round 545,999 to the nearest hundred thousand
Gnom [1K]
545,999 rounded to the nearest hundred thousand is 546,000.
6 0
2 years ago
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