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2 years ago

What is the value of 6i/1+i? 2 – 6i 2 + 6i 3 – 3i 3 + 3i

Mathematics

2 answers:

mihalych1998 [28]2 years ago

6 0

6i/ (1+i)

multiply by the complex conjugate (1-i)/(1-i)

6i/(1+i) * (1-i)/(1-i)

6i* (1-i) = 6i - 6i^2 = 6i - 6(-1) = 6i +6

(1+i)*(1-i)= 1-i +i -i^2 = 1 -i+i -(-1) = 1+1=2

(6+6i)/2

3+3i

Answer: 3+3i

alekssr [168]2 years ago

3 0

Answer:

D. 3+3i

Step-by-step explanation:

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Answer:

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2 years ago

Read 2 more answers

Which part of the proof does the fourth statement and reason represent?

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Answer:

Option B is correct.

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Step-by-step explanation:

Given: $AB \cong BC$ and $BC \cong EF$

By transitive property: a = b and b = c then, a =c

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AB = EF [def of $\cong$ segment]

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2 years ago

The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas

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with critical points at $t$ such that

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So either

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