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Sonja [21]
2 years ago
10

Credit cards place a three digit security code on the back of cards. What is the probability that a code starts with the number

7?
Mathematics
1 answer:
yan [13]2 years ago
4 0
<h2>Answer:</h2>

The probability that a code starts with the number 7 is:

                          1/10

<h2>Step-by-step explanation:</h2>

There are total 10 digits:

0   1   2    3    4   5   6   7   8   9

Also, the total number of codes that are possible using these digits are:

                            1000

( Since there are 10 choices for first place, 10 for second and 10 for third as well

Hence, total possibilities are: 10×10×10=1000 )

Also, if the first place of the code is fixed with number 7.

So, we need to chose the digits for second and third place.

Hence, total codes whose first digit is 7 are:

                      100

( Since the choice for first place is fixed and for second and third place we have 10 choices i.e. total such cases are: 1×10×10=100   )

Hence, the probability is calculated as:

            Probability=100/1000

                               =1/10

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You are at the bottom of a mountain where the temperature is 74°F. The top of the mountain is 5500 feet above you. What is the t
mamaluj [8]

For every 1,000 feet you go up in elevation, the temperature decreases by about 3.3°F

 

Given:

Temperature at the bottom of the mountain is 74°F

The top of the mountain is 5500 feet above you

 

Change (reduction) in temperature is 3.3 X 5500 / 1000

= 18.15°F

 

Temperature at the top of the mountain is 74°F – 18.15°F

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1 year ago
What is 6.37 × 104 written in standard form?   A. 63,700   B. 637,000   C. 6370   D. 637
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In short, Your Answer would be Option A

Hope this helps!
8 0
2 years ago
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Wilson has a balance of $890 on a credit card with an APR of 18.7%, compounded monthly. About how much will he save in interest
Leona [35]
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8 0
2 years ago
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PI-3.
Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

x=2q_1+1

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

x=3q_2+1

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

x=7q_6

This means x-1 is divisible by 2, 3, 4, 5 and 6 without remainder, so

x-1=2\cdot 3\cdot 2\cdot 5n=60n

Hence,

x=60n+1, \ n\in N

The smallest amount of money they could have raised is $301, because

x=60\cdot 5+1=301 is divisible by 7.

Now, the number x=60n+1 should be divisible by 7 and must be greater than 500.

So,

60n+1>500\\ \\60n>499\\ \\n>8

When n = 9,

x=60\cdot 9+1=541 is not divisible by 7.

When n = 10,

x=60\cdot 10+1=601 is not divisible by 7.

When n = 11,

x=60\cdot 11+1=661 is not divisible by 7.

When n = 12,

x=60\cdot 12+1=721 is divisible by 7.

B. The least amount of money they could have raised is $721

7 0
2 years ago
Read 2 more answers
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