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Sonja [21]
2 years ago
10

Credit cards place a three digit security code on the back of cards. What is the probability that a code starts with the number

7?
Mathematics
1 answer:
yan [13]2 years ago
4 0
<h2>Answer:</h2>

The probability that a code starts with the number 7 is:

                          1/10

<h2>Step-by-step explanation:</h2>

There are total 10 digits:

0   1   2    3    4   5   6   7   8   9

Also, the total number of codes that are possible using these digits are:

                            1000

( Since there are 10 choices for first place, 10 for second and 10 for third as well

Hence, total possibilities are: 10×10×10=1000 )

Also, if the first place of the code is fixed with number 7.

So, we need to chose the digits for second and third place.

Hence, total codes whose first digit is 7 are:

                      100

( Since the choice for first place is fixed and for second and third place we have 10 choices i.e. total such cases are: 1×10×10=100   )

Hence, the probability is calculated as:

            Probability=100/1000

                               =1/10

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Answer:

Step-by-step explanation:

Answer:

a) y-8 = (y₀-8)  , b) 2y -5 = (2y₀-5)

Explanation:

To solve these equations the method of direct integration is the easiest.

a) the given equation is

          dy / dt = and -8

         dy / y-8 = dt

We change variables

          y-8 = u

         dy = du

We replace and integrate

           ∫ du / u = ∫ dt

           Ln (y-8) = t

We evaluate at the lower limits t = 0 for y = y₀

          ln (y-8) - ln (y₀-8) = t-0

Let's simplify the equation

           ln (y-8 / y₀-8) = t

           y-8 / y₀-8 =

            y-8 = (y₀-8)

b) the equation is

            dy / dt = 2y -5

            u = 2y -5

            du = 2 dy

            du / 2u = dt

We integrate

             ½ Ln (2y-5) = t

We evaluate at the limits

            ½ [ln (2y-5) - ln (2y₀-5)] = t

            Ln (2y-5 / 2y₀-5) = 2t

            2y -5 = (2y₀-5)

c) the equation is very similar to the previous one

             u = 2y -10

             du = 2 dy

             ∫ du / 2u = dt

             ln (2y-10) = 2t

We evaluate

             ln (2y-10) –ln (2y₀-10) = 2t

               2y-10 = (2y₀-10)

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Step-by-step explanation:

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Which relationship has a zero slope?
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Answer:

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The relationship that has constant y-values is the one with zero slope. That would be the first table.

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8. Derek was observing the change in water levels in his fish pond. The table below show the change in water levels of the fish
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