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kobusy [5.1K]
2 years ago
8

Emilce pide 5 platos por semana para almorzar en la oficina. El menú ofrece 5 opciones diferentes. De cuantas maneras puede real

izar el pedido de la semana si quiere repartir los platos?
Mathematics
1 answer:
MrRissso [65]2 years ago
5 0

Answer:

120 different ways

Step-by-step explanation:

For the first lunch, Emilce has 5 options to choose,

In the second lunch, now she has only 4 options, as one was already chosen.

Then, in the third lunch, she has 3 options.

In the fourth lunch, she has 2 options.

In the last lunch, she has just 1 option.

So, the number of different ways she can order her lunches in the week is:

5 * 4 * 3 * 2 * 1 = 120

She can order in 120 different ways.

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What is the value of (5x²)³ + 16y divided by 4y for x=2 and y=3
Inessa05 [86]

Answer:

30 2/3

Step-by-step explanation:

First multiply the two exponents

Second solve 2^6

Third multiply 64 times 5 = 320

Then multiply 16 times 3

Then add sums together 368

Lastly multiply 4 times 3 then divide 368 by 12

I hope this helps :)

6 0
2 years ago
Solve for x showing work
natali 33 [55]
X = 112
See attachment file below.

Hope it helped!

5 0
2 years ago
Photon Lighting Company determines that the supply and demand functions for its most popular lamp are as follows: S(p) = 400 - 4
BlackZzzverrR [31]
S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3

S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24
6 0
2 years ago
What is the binomial expansion of (x + 2)4? x4 + 4x3 + 6x2 + 4x + 1 8x3 + 24x2 + 32x x4 + 8x3 + 24x2 + 32x + 16 2x4 + 8x3 + 12x2
Margaret [11]

<u>Answer-</u>

\boxed{\boxed{(x+2)^4=x^4+8x^3+24x^2+32x+16}}

<u>Solution-</u>

Given expression is (x+2)^4

Applying Binomial Theorem

\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

Here,

a = x, b = 2 and n = 4

So,

\left(x+2\right)^4=\sum _{i=0}^4\binom{4}{i}x^{\left(4-i\right)}\cdot \:2^i

Expanding the summation

=\dfrac{4!}{0!\left(4-0\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(4-1\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(4-2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(4-3\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(4-4\right)!}x^0\cdot \:2^4

=\dfrac{4!}{0!\left(4\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(3\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(1\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(0\right)!}x^0\cdot \:2^4

=1\cdot x^4\cdot \:1+4\cdot x^3\cdot \:2+6x^2\cdot \:4+4\cdot x\cdot \:8+1\cdot 1\cdot \:16

=x^4+8x^3+24x^2+32x+16

4 0
2 years ago
Read 2 more answers
Which graph represents the solution set for the inequality StartFraction one-half EndFraction x is less than or equal to 18.x ≤
Mrrafil [7]

Answer:

A number line from 0 to 60 in increments of 6. A point is at 36 and a bold line starts at 36 and is pointing to the left. ⇒ last answer

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- <u><em>When solving an inequality, there are some important points:</em></u>

# If the inequality is x > a, then it represented on the number line by

  a ray with empty small circle as end starts at a and pointed to

  the right (⇒ ∞)

# If the inequality is x ≥ a, then it represented on the number line by

  a ray with bold small circle as end starts at a and pointed to the

  right (⇒ ∞)

# If the inequality is x < a, then it represented on the number line

  by a ray with empty small circle as end starts at a and pointed to

  the left (⇒ -∞)

# If the inequality is x ≤ a, then it represented on the number line by

  a ray with bold small circle as end starts at a and pointed to the

  left (⇒ -∞)

* <em>Lets solve the problem</em>

∵ 1/2 x ≤ 18

- Multiply both sides by 2

∴ x ≤ 36

- To represent it draw a number line from 0 to 60 and the counted

 by 6 as 0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

- Draw a ray with bold end starts at 36 and pointed to the left

∴ A number line from 0 to 60 in increments of 6. A point is at 36 and

  a bold line starts at 36 and is pointing to the left.

3 0
2 years ago
Read 2 more answers
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