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kondor19780726 [428]

2 years ago

8

Of the 50 students in the drama club, 36 take mathematics, 27 take physics and 20 students take both mathematics and physics. Ho

w many drama club students take neither mathematics nor physics?

1 answer:

pantera1 [17]2 years ago

5 0

7

drama, maths and physics= 20

drama and physics only= 7

drama and maths only = 16

neither maths nor physics = 7+16+20-50

= 7

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A case of tomato cans weighs 563 dekagrams. A case of soup cans weighs 458 dekagrams. How much do the two cases weigh together i

oee [108]

Answer:

102,100 decigrams

Step-by-step explanation:

(564 dag + 458 dag) = 1021 dag

1021 dag × 100 dg/dag = 102100 dg

The two cases together weigh 102,100 decigrams.

_____

1 dag = 10 g

1 dg = 0.1 g

6 0

2 years ago

Read 2 more answers

6. Charlie can spend up to $8 on lunch. He wants to buy a tuna sandwich, a bottle of

PilotLPTM [1.2K]

Answer:

The maximum number of pounds of potato salad that Charlie can buy is 0.375

Step-by-step explanation:

see the attached figure to better understand the problem

Let

a ----> the cost of one tuna sandwich

b ----> the cost of a bottle of apple juice

c ----> the cost per pound of potato salad

x ----> pounds of potato salad

we have

$a=\$4.25$

$b=\$2.25$

$c=\$4.00/lb$

we know that

He wants to buy a tuna sandwich, a bottle of apple juice, and x pounds of potato salad and can spend up to $8

The inequality that represent this situation is

$a+b+cx \leq 8$

substitute the given values

$4.25+2.25+4.00x \leq 8$

Solve for x

Combine like terms

$6.50+4.00x \leq 8$

Subtract 6.50 both sides

$4.00x \leq 8-6.50$

$4.00x \leq 1.50$

Divide by 4 both sides

$x \leq 1.50/4.00$

$x \leq 0.375\ lbs$

therefore

The maximum number of pounds of potato salad that Charlie can buy is 0.375

3 0

2 years ago

Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.

alexdok [17]

Answer:

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There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9

Therefore for each and every one of the nine first digits there are 5 digits that the second can be.

Therefore ANSWER = 9 * 5 = 45 possible permutations.

2. The largest two digit number = 99

Subtract 57 and you get 42

ANSWER = 42

The forty two numbers are 58 ,59, 60, 61......98, 99

7 0

2 years ago

Read 2 more answers

We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys

marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation

$\bar X=19.2$ represent the battery life sample mean

$\sigma=2.5$ represent the population standard deviation

$n=25$ sample size

$\mu_o =18$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:

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Alternative hypothesis: $\mu \neq 18$

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis: $\mu \leq 18$

Alternative hypothesis: $\mu > 18$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

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3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4$

4) P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=25-1=24$

Since is a two tailed test for parts I and II, the p value would be:

$p_v =2*P(t_{(24)}>2.4)=0.0245$

And for part III since we have a one right tailed test the p value is:

$p_v =P(t_{(24)}>2.4)=0.0122$

5) Conclusion

I. This finding is significant for a two-tailed test at .05.

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II. This finding is significant for a two-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the $p_v >\alpha$ . We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

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2 years ago

An object is dropped from a height of 1700 ft above the ground. The function h=-16t^2+1700 gives the object’s height h in feet d

Softa [21]

The answer is
<span>a) 1000=-16t^2+1700, implies t² = -700 /-16, and t= 6.61s
b) </span><span>970= -16t^2+1700, </span><span>implies t² = -730 /-16, and t=6.75s

c)
reasonable domain of h
h is polynomial function, so its domain is R, (all real number)
its range
the inverse of h is h^-1 = sqrt (1700- t / 16), and its domain is </span>
<span><span><span>1700- t / 16>=0, so t <1700,
the range of h is I= ]-infinity, 1700]</span> </span> </span>

8 0

2 years ago