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AleksandrR [38]

2 years ago

5

A Teacher has a bag of 100 unit cubes. She gives an equal number of cubes to each of the seven groups in her class. She gives ea

ch group as many cubes as she can. How many unit cubes are left over?

1 answer:

ch4aika [34]2 years ago

4 0

There will be 2 cubes left over, because 14X7 is 98 and you can't go any higher than that.

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In a school building, there are 8 exterior doors and 12 stairways to enter the second floor. Find a total number of ways to reac

Kazeer [188]

To reach the second floor you would look at all ways to enter to building(8) and multiply it by the number of ways to reach the second floor (12).

8 x 12 = 96 possibilities

Think of it in groups.

1st door and 12 possible sets of steps
2nd door and 12 possible sets of steps
3rd door and 12 possible sets of steps
4th door and 12 possible sets of steps
5th door and ..., etc.....

7 0

2 years ago

Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b

horrorfan [7]

Answer:

a. $X\sim N(\mu = 6.1, \sigma = 1.9)$ b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is $z_{1} = (6.4-6.1)/1.9 = 0.1579$ and the z-score related to 7 kg is $z_{2} = (7-6.1)/1.9 = 0.4737$ , we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0

2 years ago

Aileen can read 1.5 pages for every page her friend can read. Aileen's mom was very excited and she said to Aileen: "So, if your

dalvyx [7]

No, Aileen's mom is incorrect. Aileen can read 30 pages in the same time period as her friend reads 20 pages.

To get this answer, you multiply 20 by 1.5

20 x 1.5 = 30

8 0

2 years ago

Read 2 more answers

Data from 14 cities were combined for a 20-year period, and the total 280 city-years included a total of 107 homicides. After

leonid [27]

Answer:

P(0) = 0.6825

P(1) = 0.2607

Step-by-step explanation:

From the given information, the number of homicide is 107 and the total number of homicides per city –year is 280.

Let us denote the number of homicides per city-year as X.

The mean value, X is calculated as:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}

Mean= 107/280 = 0.382

The mean number of homicides per city- year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. The probability that zero homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}

P(X=0) = e −0.382 (0.382)⁰/1

= (0.6825)(1) /1

P(X=0) = 0.6825

Thus, the probability that zero homicides P(0) is 0.6825.

b. The probability that one homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}

P(X=1) = e −0.382 (0.382)¹/1

= (0.6825)(0.382)/1

P(X=1) = 0.2607

Thus, the probability that zero homicides P(0) is 0.2607.

5 0

2 years ago

2. Let f(x) = 3x² -x+5, find f(x+1)

Anna11 [10]

Answer:

f(x + 1) = 3x² + 5x + 7

Step-by-step explanation:

To find f(x + 1), substitute x = x + 1 into f(x), that is

f(x + 1) = 3(x + 1)² - (x + 1) + 5 ← expand (x + 1)² using FOIL

= 3(x² + 2x + 1) - x - 1 + 5 ← distribute parenthesis by 3

= 3x² + 6x + 3 - x - 1 + 5 ← collect like terms

= 3x² + 5x + 7

8 0

2 years ago