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olganol [36]
2 years ago
12

Suppose there is a 20% chance of rain on Monday and a 40% chance of rain on Tuesday. Assuming the weather on successive days is

independent, find
a. the probability it rains on Monday or Tuesday.
b. the conditional probability it rains on Tuesday given that it rained on Monday.
Mathematics
1 answer:
nadya68 [22]2 years ago
4 0

Answer:

a. 52%

b. 40%

Step-by-step explanation:

Let A represents the event of raining on Monday and B represents the event of raining in Tuesday,

Then according to the question,

P(A) = 20% = 0.2,

P(B) = 40% = 0.4,

Here, A and B are independent events,

So, P(A∩B) = P(A) × P(B),

⇒ P(A∩B) = 0.2 × 0.4 = 0.08

We know that,

P(A∪B) = P(A) + P(B) - P(A∩B)

a. The probability it rains on Monday or Tuesday, P(A∪B) = 0.2 + 0.4 - 0.08

= 0.52

= 52%

b. The conditional probability it rains on Tuesday given that it rained on Monday,

P(\frac{B}{A})=\frac{P(A\cap B)}{P(A)} = \frac{0.08}{0.2}=0.4 = 40\%

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The sum of the interior angles of a polygon is
Crank

Answer:

D) 15

Step-by-step explanation:

The sum of the interior angles of a polygon is given by

(n - 2) \times 180

We have that, the sum of the interior angles of a polygon is

26 right angles. We want to find n, the number of sides.

We substitute into the formula to get:

(n - 2) \times 180 = 26 \times 90

Divide through by 90

2(n - 2) = 26

Divide through by 2

n - 2 = 13

n = 13 + 2

n = 15

6 0
2 years ago
There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet
lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

\frac{2}{5} = \frac{x}{340,000}

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

3 0
2 years ago
Read 2 more answers
Find the value of a/b when a = $13.93 and b= 0.07
lara [203]

Answer:

If you divide the numbers you should get 199.



5 0
2 years ago
96.5 times 2.54 i know the answer i just need help showing the work
kogti [31]
You just solve it like a normal multiplication problem and then start putting the decimal begin the answer and place it 3 numbers forward
3 0
2 years ago
Read 2 more answers
Solve the following multiplication and division problems. a. 8 T. 1,398 lb. 14 oz. × 6 b. 349 lb. 6 oz. ÷ 130 c. 6 T. 294 lb. ÷
tester [92]

Answer:  a) 278382 oz

b) 43 oz

c) 64.1 oz

Step-by-step explanation:

a) 8 T. 1,398 lb. 14 oz. × 6

First we need to change it in 'oz'.

As we know that

1\ ton=32000\ oz\\\\1\ lb=16\ oz

so, it becomes,

8\times 32000+1398\times 16+14\ oz\\\\=278382\ oz

8 T. 1,398 lb. 14 oz. × 6 becomes

278382\times 6\\\\=1670292\ oz

b) 349 lb. 6 oz. ÷ 130

It becomes,

349\times 16+6\ oz\\\\=5590\ oz\\\\\text{ at last it becomes}\\\\=\frac{5590}{130}\\\\=43\ oz

c) 6 T. 294 lb. ÷ 3,071

First it becomes,

6\times 32000+294\times 16\ oz\\\\=196704\ oz

At last it becomes,

\frac{196704}{3071}\\\\=64.1\ oz

Hence, a) 278382 oz

b) 43 oz

c) 64.1 oz

6 0
2 years ago
Read 2 more answers
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