Answer:
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
equate to zero
so
substitute in the formula
therefore
StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction
The confidence interval would be (0.122, 0.278).
We first find our z-score. We want a 95% confidence interval:
0.95/2 = 0.475
Looking this up in the z-table, (http://www.statisticshowto.com/tables/z-table/) we see the z-score is 1.96.
The formula we will use is:

In this problem, p = 20/100 = 0.2, and n=100:
Answer:
8minutes per mile
Step-by-step explanation:
You ran 3 miles since 9am divide 24 by 3 to get 8 minutes
Answer:
Al comienzo Juana tiene 28 libras de azúcar.
Ella hace 6 paquetes de 2.5kg cada paquete.
Entonces, entre los 6 paquetes, hay:
6*2.5kg = 15kg de azúcar.
Ahora el problema es que tenemos dos unidades distintas, kilogramos y libras.
Aca podemos usar la relación:
1k = 2.2lb.
Entonces 15kg de azúcar son 15 veces 2.2 libras:
15kg = 15*2.2lb = 33lb.
Esto nos da mas de lo que hay originalmente en el costal.
Ahora si lo pensamos como:
Solo vendió 5 paquetes de 2.5kg, entonces el sobrante queda en el costal inicial:
5*2.5kg = 12.5kg
De vuelta, 1kg = 2.2lb
12.5kg = 12.5*2.2lb = 27.5lb
En este caso hay un sobrante de:
28lb - 27.5lb = 0.5lb
Here's what we'll be evaluating:
24 2/3 - 5/6 24 4/6 - 5/6 23 10/6-5/6 23 5/6
------------------- = -------------------- = -------------------- = ----------------------
11 pieces 11 pieces 11 pieces 11 [pieces
Now, this 23 5/6 is equivalent to 143/6, which we must divide by 11:
143 1
------ * ---------- = 13/6 (feet)
6 11
Each piece will be 13/6 ft long (2 1/6 ft).