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1 year ago

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Question 1 (1 point) The yearly interest payable on a deposit of $250 at 5.5% p.a. simple interest is: A $137.50 B $13.75 C $12.

50 D $125.00 E $17.35 los

1 answer:

dlinn [17]1 year ago

6 0

Answer:

B: $13.75

Step-by-step explanation:

5.5% of $250 = $13.75

Therefore, the simple interest is $13.75.

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How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x

Firlakuza [10]

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

$\dfrac{1}{2}(x+12)=4x-1$

Multiply this equation by 2:

$2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)$

Use distributive property:

$x+12=8x-2$

Combine the like terms:

$x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2$

Thus, this equation has one solution x = 2

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2 years ago

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To find the area of parallelogram RSTU, Juan starts by drawing a rectangle around it. Each vertex of parallelogram RSTU is on a

shusha [124]

Answer:

C. (18+4)

Step-by-step explanation:

The answer on ed

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2 years ago

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A giraffe measures 17 feet tall . A gorilla mesures 63 inches tall. How many feet taller is the giraffe than the gorilla

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Answer:

11.75 feet

Step-by-step explanation:

17 times 12 = 204 inches

204 - 63 = 141 inches

141/12 = 11.75 feet

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2 years ago

In a game of cornhole, Sasha tossed a bean bag and it landed at the edge of the hole. The hole can be represented by the equatio

Nitella [24]

In the game of cornhole, when Sasha tossed a bean bag to the edge of the hole, in which the equations of the hole and bean bag's path are x² + y² = 5 and y = 0.5x² + 1.5x - 4, respectively, she could have tossed her bean bag to the points (1, -2) or (2, 1).

To find the points in which she could have tossed her bean bag, we need to intersect the two equations of the function as follows.

<u>The equation for the hole</u>

$x^{2} + y^{2} = 5$ (1)

<u>The equation for the path of the bean bag</u>

$y = 0.5x^{2} + 1.5x - 4$ (2)

By entering equation (2) into (1) we have:

$x^{2} + (0.5x^{2} + 1.5x - 4)^{2} = 5$

$x^{2} + 0.25x^{4} + 1.5x^{3} - 4x^{2} + 2.25x^{2} - 12x + 16 = 5$

$0.25x^{4} + 1.5x^{3} - 0.75x^{2} - 12x + 11 = 0$

By solving for <em>x</em>, we have:

x₁ = 1

x₂ = 2

Now, for <em>y</em> we have (eq 2):

<u>x₁ = 1</u>

$y_{1} = 0.5(1)^{2} + 1.5(1) - 4 = -2$

<u>x₂ = 2</u>

$y_{2} = 0.5(2)^{2} + 1.5(2) - 4 = 1$

Therefore, the points are (1, -2) or (2, 1).

To find more about intersections, go here: brainly.com/question/4977725?referrer=searchResults

I hope it helps you!

8 0

2 years ago

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/ x + 60 . How m

Luba_88 [7]

Answer:

Step-by-step explanation:

Suppose the cost C(x), to build a football stadium of x thousand square feet is approximated by C(x) = 7,250,000/x + 60. Given the function, we can substitute values for x to determine the cost of a particular size of stadium or we can substitute values for C(x) to determine the number of square feet.

if the cost of the stadium was $8,000, the, we would determine the size of the stadium, x by substituting x $8,000 for C(x). It becomes

8000 = 7250,000/x + 60

8000 - 60 = 7250000/x

7940 = 7250000/x

7940x = 7250000

x = 7250000/ 7940

x = 913 ft^2

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2 years ago