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AnnyKZ [126]
2 years ago
14

A farmer plans to fence a rectangular corral. The diagonal distance from one corner of the corral to the opposite corner is five

yards longer than the width of the corral. The length of the corral is three times the width. Find the length of the diagonal of the corral. Round your answer to the nearest tenth.
Mathematics
1 answer:
garik1379 [7]2 years ago
4 0

Answer:

Length of diagonal is 7.3 yards.

Step-by-step explanation:

Given: The diagonal distance from one corner of the corral to the opposite corner is five yards longer than the width of the corral. The length of the corral is three times the width.

To find: The length of the diagonal of the corral.

Solution: Let the width of the rectangular garden be <em>x</em> yards.

So, the length of the diagonal is x+5

width of the rectangular corral is 3x

We know that the square of the diagonal is sum of the squares of the length and width.

So,

(3x)^{2} +x^{2} =(x+5)^{2}

9x^{2} +x^{2} =x^{2}+10x+25

9x^{2}-10x-25=0

9x^{2}-10x-25=0

x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a}

x=\frac{10\pm\sqrt{(-10)^{2} -4(9)(-25)} }{2(9)}

x=\frac{10\pm\sqrt{100}}{18}

Since, side can't be negative.

x=\frac{5}{9}+\frac{5}{9}\sqrt{10}

Now, length of the diagonal is

5+\frac{5}{9}+\frac{5}{9}\sqrt{10}

Hence, length of diagonal is 7.3 yards.

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Triangle A has a height of 2.5\text{ cm}2.5 cm2, point, 5, start text, space, c, m, end text and a base of 1.6\text{ cm}1.6 cm1,
konstantin123 [22]

Answer:

Option A

Option D

Option E

Step-by-step explanation:

we know that

If the height and base of triangle B are proportional to the height and base of triangle A

then

Triangle A and Triangle B are similar

Remember that

If two triangles are similar then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

\frac{h_A}{h_B} =\frac{b_A}{b_B}

where

h_A and h_B are the height of triangle A and triangle B

b_A and b_B are the base of triangle A and triangle B

In his problem we have

h_A=2.5\ cm\\b_A=1.6\ cm

substitute

\frac{2.5}{h_B} =\frac{1.6}{b_B}

Rewrite

\frac{2.5}{1.6} =\frac{h_B}{b_B}

\frac{h_B}{b_B}=1.5625

<u><em>Verify all the options</em></u>

A) we have

h_B=2.75\ cm\\b_B=1.76\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2.75}{1.76}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

B) we have

h_B=9.25\ cm\\b_B=9.16\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{9.25}{9.16}=1.0098

The ratios are not equal

That means that are not proportional

therefore

These values could not be the height and base of triangle B

C) we have

h_B=3.2\ cm\\b_B=5\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{3.2}{5}=0.64

The ratios are not the same

That means that are not proportional

therefore

These values could not be the height and base of triangle B

D) we have

h_B=1.25\ cm\\b_B=0.8\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{1.25}{0.8}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

E) we have

h_B=2\ cm\\b_B=1.28\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2}{1.28}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

8 0
2 years ago
7. Tamara goes on a spring break trip with her school to visit historical sites in Italy. She purchases $200 of souvenirs while
fgiga [73]

Answer:

b

Step-by-step explanation:

6 0
2 years ago
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1. Contaminated water is subjected to a cleaning process. The concentration of the pollutants is initially 5 mg per liter of wat
Art [367]

Answer:

C(t)=5\cdot(0.9)^t

Step-by-step explanation:

The exponential function is often used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The concentration of the pollutants starts at Co=5 mg/lt. We also know the pollutant reduces its concentration by 10% each hour. This gives us a value of r = 10% / 100 = 0.1

Substituting into the general equation:

C(t)=5\cdot(1-0.1)^t

Operating:

\boxed{C(t)=5\cdot(0.9)^t}

7 0
2 years ago
A baseball glove is on sale for $34.00, which is 15% off of its original price. What was the original price of the baseball glov
Y_Kistochka [10]

Answer: $40.00

Step-by-step explanation:

To find the original price, you would need to utilize the equation Original Price = Sales Price ÷ (1 - Discount). In this equation, Discount refers to the percentage of discount.

Original Price = $34.00 ÷ (1 - 0.15)

Original Price = $34.00 ÷ (0.85)                      

Original Price = $40.00

3 0
2 years ago
Which equation represents a line that passes through (5, 1) and has a slope of StartFraction one-half EndFraction?
saul85 [17]

Answer:

y – 1 = y minus 1 equals StartFraction one-half EndFraction left-parenthesis x minus 5 right-parenthesis.(x –5)

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

we have

m=\frac{1}{2}

(5,1)

substitute

y-1=\frac{1}{2}(x-5)

5 0
2 years ago
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