Question

Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take a random sample of 25. When sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. The mean of this situation is?

Answer 1

Answer:

The mean of this situation is 4.25

Step-by-step explanation:

Given,

the number of computer components = 400

No of defective computer components=

Probability of selecting a defective computer =$\frac{68C1}{400C1}$=0.17

Mean of this situation = n×p

where n is no of random sample

Therefore, Mean= 25×0.17=4.25