The probability that the first stage of a numerically controlled machining operation for high-rpm pistons meets specifications i
1 answer:
Answer:
There is an 85.5% probability that both stages meet specifications.
Step-by-step explanation:
We have these following probabilities:
A 90% probability that the first stage meets specifications.
If the first stage meets specifications, a 95% probability that the second stage also meets specifications.
What is the probability that both stages meet specifications?
This is the multiplication of these probabilities. So:
There is an 85.5% probability that both stages meet specifications.
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Answer:
a)
b)
Step-by-step explanation:
1) Data given and notation
n=900 represent the random sample taken
X=372 represent the students were pursuing liberal arts degrees
estimated proportion of students were pursuing liberal arts degrees
represent the significance level
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
p= population proportion of students were pursuing liberal arts degrees
2) Solution to the problem
The confidence interval would be given by this formula
For the 99% confidence interval the value of and
, with that value we can find the quantile required for the interval in the normal standard distribution.
The margin of error is given by:
If we replace we have:
And replacing into the confidence interval formula we got:
And the 99% confidence interval would be given (0.371;0.455).
We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.
Answer:
369 students have taken a course in either calculus or discrete mathematics
Step-by-step explanation:
I am going to build the Venn's diagram of these values.
I am going to say that:
A is the number of students who have taken a course in calculus.
B is the number of students who have taken a course in discrete mathematics.
We have that:
In which a is the number of students who have taken a course in calculus but not in discrete mathematics and is the number of students who have taken a course in both calculus and discrete mathematics.
By the same logic, we have that:
188 who have taken courses in both calculus and discrete mathematics.
This means that
212 who have taken a course in discrete mathematics
This means that
345 students at a college who have taken a course in calculus
This means that
How many students have taken a course in either calculus or discrete mathematics
369 students have taken a course in either calculus or discrete mathematics