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gladu [14]
2 years ago
14

The ordered pairs model an exponential function, where w is the function name and t is the input variable. {(1, 60), (2, 240), (

3, 960), (4, 3840)}{(1, 60), (2, 240), (3, 960), (4, 3840)} What is the function equation in sequence notation? Enter your answer in the box.
Mathematics
2 answers:
kompoz [17]2 years ago
7 0
Hello there.
<span>
The ordered pairs model an exponential function, where w is the function name and t is the input variable. {(1, 60), (2, 240), (3, 960), (4, 3840)}{(1, 60), (2, 240), (3, 960), (4, 3840)} What is the function equation in sequence notation? Enter your answer in the box.
</span>
w = 15 (4^t)
alexandr1967 [171]2 years ago
3 0
We are given the set of points
<span>{(1, 60), (2, 240), (3, 960), (4, 3840)}{(1, 60), (2, 240), (3, 960), (4, 3840)} 
If w is the function name and t is the input variable, then the equation has the form
w = k a^t
Plugging in any two of the points to solve for k and a
Choosing </span>(1, 60) and (2, 240)<span>
60 = k a
k = 60 / a

240 = k a^2

Substituting
240 = 60/a (a^2)
a = 4
and
k = 60 / 4 = 15

The function is 
w = 15 (4^t)</span>
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The measure of ADB is 162 . what is the measure of EAB?
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An angle formed by a chord and a tangent line is half the measure of the intercepted arc.

 The intercepted arc is ADB, which is given as 162 degrees.

Angle EAB = 1/2 of 162

The answer is 81 degrees.

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What is the word form of 34/100
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34/100
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Karson drove from his house to work at an average speed of 35 miles per hour.  The drive took him 20 minutes.  If the drive took
Nastasia [14]

Answer:

Karson's average speed on his way home was 28 miles per hour.

Step-by-step explanation:

Since Karson drove from his house to work at an average speed of 35 miles per hour, and the drive took him 20 minutes, if the drive took him 25 minutes and he used the same route in reverse, to determine what was his average speed going home, the following calculation must be performed:

60 = 35

20 = X

20 x 35/60 = X

700/60 = X

11.666 = X

25 = 11,666

60 = X

60 x 11.666 / 25 = X

27.99 = X

Therefore, Karson's average speed on his way home was 28 miles per hour.

3 0
1 year ago
Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
1 year ago
Read 2 more answers
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
2 years ago
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