10% of $560 is $56
So 5% is $28
1% of $560 is $5.60
So now half $5.60 is $2.80
$2.80 is 0.05%
Now add
$28 + $2.80 = $30.80
Total is $30.80
Answer:
Strawberries sold 44 baskets
Raspberries sold 52 baskets
Step-by-step explanation:

Answer:
Follows are the solution to this question:
Step-by-step explanation:
Recommendation from the American Chiropractic Association:
No more than
of body weight should be borne through kids
Third classification:
More than
of its weight:
ACA Suggestion proportion of children 
Fifth degree:
Over
of body weight:
ACA Suggestion for children 
ACA suggestion doesn't quite follow either majority for third and fifth grades: fifth grades (68.18%) are marginally hyper-third grades (66.67%).
Answer:
a.[144;158]$
b. The parameter estimated is the population mean of the weekly expenses on the food of American families.
Step-by-step explanation:
Hello!
The study variable for this problem is "Weekly expenses on food spent by an American family"($)
For a sample n=1014 American families the corresponding sample mean is x[bar]=$151
It is stated that for the 95%CI the margin of error is ±$7
a.
The confidence interval that estimates the population mean is constructed as the "estimator ± margin of error" for example, under a Standard Normal distribution the formula for the confidence interval is:
[x[bar]±
*(δ/√n)]
For the sample taken it is:
[151±7]
The inferior limit is 144$
The superior limit is 158$
b.
The parameter estimated is the population mean of the weekly expenses on the food of American families.
The confidence level of an interval is the probability under which it is built. This probability indicates that if they build 100 confidence intervals, we expect 95 to contain the value of the population mean we are trying to estimate.
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