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jeka94
2 years ago
5

You have 3 online accounts in three different banks valued at: bank "A" = $250.67, 12% interest, bank "B" $765.13, 7% interest,

and bank "C" $28,500.36, 9% interest. What is the average interest gained from the three accounts in one year?
Mathematics
1 answer:
gregori [183]2 years ago
3 0

Answer:

\$882.89

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

Bank A

t=1\ years\\ P=\$250.67\\r=12\%=12/100=0.12

substitute in the formula above

I=250.67(0.12*1)=\$30.08

Bank B

t=1\ years\\ P=\$765.13\\r=7\%=7/100=0.07

substitute in the formula above

I=765.13(0.07*1)=\$53.56

Bank C

t=1\ years\\ P=\$28,500.36\\r=9\%=9/100=0.09

substitute in the formula above

I=28,500.36(0.09*1)=\$2,565.03

Find the average interest gained from the three accounts in one year

[\$30.08+\$53.56+\$2,565.03]/3=\$882.89

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Answer:

0.25

Step-by-step explanation:

72% of courses have final exams and 46% of courses require research papers which means probability of 0.72 for courses that have final exams and 0.46 for courses that require research papers.

31% of courses have a research paper and a final exam, which means probability of 0.31 for both courses with exams and research papers, using Venn diagram approach, find picture attached to the solution.

P(R or E) = P(R) + P(E) - P(R and E), which gives:

P(R or E) = 0.15 + 0.41 - 0.31

P(R or E) = 0.25.

6 0
2 years ago
Mikela claims that the sum of any two numbers is greater than the larger of the two numbers. Jim claims that the sum of any two
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<u>ANSWER:  </u>

The statement of Jim is correct

<u>SOLUTION:  </u>

Given statements are  

Mikela claims that sum of any two numbers is greater than the larger of the two numbers.  

Jim claims that the sum of any two natural numbers is greater than the larger of the two numbers.

Let a,b be the two numbers and a is the greatest of a and b

According to the mikela statement = a + b > a

b > a – a

b > 0

Here, we got an condition that b > 0, but it may not be true always.  

Above condition fails when b is either 0 or negative number.  

Jim - sum of any two natural numbers is greater than the larger of the two numbers.

Let a,b be the two natural numbers. And a is the greatest of a and b

According to the jim statement  =  a + b > a

b > a – a

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What is the recursive rule for an=4n−1? a1=4;an=an−1−1 a1=3;an=an−1+4 a1=−1;an=an−1+4 a1=3;an=an−1−1
navik [9.2K]
Plug in n = 1 into the nth term formula
a(n) = 4n-1
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So the nth term is found by adding 4 to the (n-1)st term, in other words,
a(n) = a(n-1)+4

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In summary, the answer is 
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which is choice B
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Answer:

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