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Rom4ik [11]
1 year ago
14

If a is an arbitrary nonzero constant, what happens to a/b as b approaches 0

Mathematics
1 answer:
Stolb23 [73]1 year ago
7 0

It depends on how b approaches 0

If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.

On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.

The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.

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Triangle R T S is sitting on a horizontal line. Line S R extends through point Q to form exterior angle T R Q. Angle R T S is (2
Firlakuza [10]

Answer:

The value of x is 3 ⇒ 2nd answer

Step-by-step explanation:

<u><em>An exterior angle</em></u> is the angle between one side of a triangle and the

extension of an adjacent side

<u><em>The measure of an exterior angle at any vertex of a triangle equal the </em></u>

<u><em>sum of the measures of the two opposite interior angles</em></u>

- Triangle R T S is sitting on a horizontal line

- Line S R extends through point Q to form exterior angle T R Q

- m∠RTS is (25 x)°, m∠TSR is (57 + x)° , m∠TRQ is (45 x)°

* Lets find the value of x

∵ ∠TRQ is an exterior angle of Δ RTS at the vertex R

∵ The opposite interior angles to vertex R are ∠RTS and ∠TSR

∴ m∠TRQ = m∠RTS + m∠TSR ⇒ <u><em>as the rule above</em></u>

∵ m∠TRQ = (45 x)°

∵ m∠RTS = (25 x)°

∵ m∠TSR = (57 + x)°

Substitute these measures in the equation above

∴ 45 x = 25 x + 57 + x

∴ 45 x = 26 x + 57

Subtract 26 x from both sides

∴ 19 x = 57

Divide both sides by 19

∴ x = 3

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3 0
2 years ago
Read 2 more answers
Dev has 9 shells. Zoe has 55 shells, Zoe gives some shells to Dev. Now zoe has 3 times as many shells as dev. How many shells do
Goryan [66]

Answer:

number of shells zoe gives to dev  = 7

number of shells zoe is left with  = 55-7= 48

number of shells dev has = 9+7=16

Step-by-step explanation:

let the initial number of shells that dev has be A, and initial number of shells that zoe has be B.

let the number of shells that zoe gives to dev be x.

after giiving x shells zoe is left with 3 times the number of shell as that of dev.

therefore number of shells with zoe = 3×number of shells with dev.

number of shells with zoe = initial shells - x = 55-x

number of shells with dev = initial shells + number of shells he gets

                                            = 9+x

therefore (55-x)=3×(9+x)

55-x = 27+3x

55-27=3x+x

4x = 28

x= 7

therefore number of shells zoe gives to dev  = 7

number of shells zoe is left with  = 55-7= 48

number of shells dev has = 9+7=16

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Answer:

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Step-by-step explanation:

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Thus,

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2765 \div 0.79 = 3500

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