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Rom4ik [11]
2 years ago
14

If a is an arbitrary nonzero constant, what happens to a/b as b approaches 0

Mathematics
1 answer:
Stolb23 [73]2 years ago
7 0

It depends on how b approaches 0

If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.

On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.

The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.

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Answer:

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Step-by-step explanation:

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Multiplying both sides by x, we have,

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So the  fraction represents the decimal \overline{0.12} is: \frac{3}{25}

Hope it well find you well.

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