We have been given an equation
. We are asked to solve the equation for t.
First of all, we will divide both sides of equation by a.


Now we will take natural log on both sides.

Using natural log property
, we will get:

We know that
, so we will get:


Now we will divide both sides by c as:


Therefore, our solution would be
.
Answer:
No. of gonjas = 52
No. of more nzemas than fantes = 78
Step-by-step explanation:
Total no. of people = 520
No. of fantes =
× 520
No. of fantes = 156
No. of ewes =
× 520 = 130
No. of nzemas =
× 520 = 78
No. of gas =
× 520 = 104
No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52
No. of fantes = 156
No. of nzemas = 78
No. of more nzemas than fantes = 156 - 78 = 78
Pie chart of the following problem is shown below.
For this problem, here’s how you do it.
Assuming the velocity is as written,
a = 3(2) = 6
If you meant 3(2t+1)⁰.⁴, then
a = 2.4/(2t+1)⁰.⁶
as usual,
s = 25 + 1/2 at²
= 25 + 3t²
or
= 25 + 1.2(2t+1)¹.⁴
Answer:
(5x²+2y² + 2xy)(5x²+2y²-2xy)
Step-by-step explanation:
25x⁴+4x²y²+4y⁴= (5x²)²+2*5x²*2y²+(2y²)² - 16x²y²= (5x²+2y²)² - (4xy)²= (5x²+2y² + 2xy)(5x²+2y² - 2xy)