Answer:
The number of dogs that had both Lyme disease and arthritis is 18
Step-by-step explanation:
Let x represent dogs that have both Lyme disease and arthritis
Dog with only Lyme disease = 42 - x
Dog with only arthritis = 96 - x
The sum of the 3 category should give 120
x + (42 - x) + (96 - x) = 120
Collect like terms and solve
x - x - x + 42 + 96 = 120
-x + 138 = 120
138 - 120 = x
x = 18
Dog with only Lyme disease = 42 - x = 42 - 18 = 24
Dog with only arthritis = 96 - x = 96 - 18 = 78
Therefore, the number of dogs with both Lyme disease and anthritis is 18.
A book is sold in Belize for 80.39 Belize dollars.
In Brazil, it sells for 63.65 Brazilian reals.
The exchange rate of US Dollars to Belize Dollars is 1:1.9246
<span>The exchange rate of US Dollars to Brazilian Real is 1:1.7880
</span>
If we convert the two into dollars,
Belize Dollars
1 : 1.9246 = X : <span>80.39
1.9246X = 80.39
X = $ 41.77
</span>Brazilian Real
1 : 1.7880 = X : 63.65 <span>
</span>1.7880X = 63.65 <span>
X = $ 35.60
</span>
Difference = $ 41.77 - $ 35.60
Difference = $ 6.17
<span>So, in Belize the book is more expensive by $ 6.17</span>
Step 1: If there is a common factor, factor out the GCF. Step 2<span>: Identify the number of terms: (i) If polynomial has two terms, convert polynomial into difference of two squares or sum of two cubes or difference of two cubes.</span>
Answer:
X=7 ST=11 RT=17
Step-by-step explanation:
RT=RS+ST. RS= 2(7)-8. ST=11
X+10=2x-8+11. =14-8=6. RT= x+10
X+10=2x+3. RS=6. 7+10=17
10=x+3. RT=17
X=7