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Flauer [41]
2 years ago
13

Julian is using a biking app that compares his position to a simulated biker traveling Julian's target speed. When Julian is beh

ind the simulated biker, he has a negative position. Julian sets the simulated biker to a speed of 20\,\dfrac{\text{km}}{\text{h}}20 h km ​ 20, space, start fraction, k, m, divided by, h, end fraction. After he rides his bike for 151515 minutes, Julian's app reports a position of -2\dfrac{1}{4}\,\text{km}−2 4 1 ​ kmminus, 2, start fraction, 1, divided by, 4, end fraction, space, k, m. What has Julian's average speed been so far?
Mathematics
1 answer:
Gwar [14]2 years ago
5 0

Answer:

11 km/hr.

Step-by-step explanation:

Given information:

Simulated speed = 20/km/h

Time = 15 mins = 1/4 hr = 0.25 hr

Distance Covered as per simulated speed = 20\times \frac{1}{4}=5km

Position of Julian according to the app = -2\frac{1}{4}=-2.25.

Actual distance covered by the bike is

Distance= 5 - 2.25 = 2.75km

Formula for speed:

\text{Average Speed}=\frac{Distance}{Time}

\text{Average Speed}=\frac{2.75}{0.25}

\text{Average Speed}=11

Therefore, the average speed of Julian is 11 km/hr.

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ale4655 [162]

Answer:

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Step-by-step explanation:

8 0
1 year ago
Alissa has $360 for guitar lessons. She pays $25 for each lesson. How many lessons has she attended, if she still has $85 left?
bagirrra123 [75]

Answer:

11 lessons

Step-by-step explanation:

360-85=275

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7 0
2 years ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
2 years ago
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Feliz [49]

Answer:

Step-by-step explanation:

a )

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(18.92 + 19.25 ..... + 22.43 + 22.85) / 16

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c )

We can easily plot the data on number line from 17 to 24

d )

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4 0
2 years ago
suppose the commute times for employees of a large company follow a normal distribution. if the mean time is 18 minutes and the
stepladder [879]

Answer:I think A

Step-by-step explanation:

Hopefully I am right

4 0
2 years ago
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