We are given the function <span>–2x – 4 + 5x = 8 and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:
-2x + 5x =8+4
Then, do the necessary operations.
3x = 12
x = 4.
The variable x has a value of 4.</span>
Answer:
She traveled a total of 2875 metres during practice.
Step-by-step explanation:
Doris ran 2.5 kilometres, then sprinted 300 meters and finally walked 1/4 of the distance she sprinted.
To find the total distance that she traveled, we simply add the distance that she ran, sprinted and walked.
We will convert all distances to metres.
She ran 2.5 kilometres:
1 km = 1000 m
2.5 km = 2.5 * 1000 = 2500 m
So, she ran 2500 m.
She sprinted 300 m.
Se walked 1/4 the distance that she sprinted:
1/4 * 300 = 75 m
She walked 75 m.
Therefore, the total distance she traveled is:
2500 + 300 + 75 = 2875 m
She traveled a total of 2875 metres during practice.
Answer:
The coefficients are
11,-4 and 0
Step-by-step explanation:
We are given two algebraic expressions. We are subtracting the second from the first.
First one is
Second expression is
The given expression
=
The coefficients are
11,-4 and 0
Answer:
Step-by-step explanation:
Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = points scored by students
u = mean time
s = standard deviation
From the information given,
u = 102 minutes
s = 18 minutes
1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as
P(x > 120 minutes) = 1 - P(x ≤ 120)
For x = 120
z = (120 - 102)/18 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x > 120) = 1 - 0.8413 = 0.1587
2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as
P(x < 66 minutes)
For x = 66
z = (66 - 102)/18 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.02275
P(x < 66 minutes) = 0.02275
