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jonny [76]
1 year ago
9

Consider △RST and △RYX.

Mathematics
2 answers:
il63 [147K]1 year ago
7 0
We look at what is provided and our answers give us a clue on this. We see we are to compare using fractions...always being the part / whole.  This is so we can compare to make similarities...

B....RY/RS = RX/RT = XY/TS
Scilla [17]1 year ago
5 0

Answer:

option B

\frac{RY}{RS}=\frac{RX}{RT}=\frac{XY}{TS}

Step-by-step explanation:

we know that

If two triangles are similar

then

The ratio of their corresponding sides are equal and their corresponding angles also are equal

so

\frac{RY}{RS}=\frac{RX}{RT}=\frac{XY}{TS}

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GRAHAM CORPORATION
astra-53 [7]

Answer:

<h2>Net proceed= s-0.98nd-11</h2>

Step-by-step explanation:

Given that the shares cost $d

n shares will be =$dn

paid 2% commission to her broker= (2/100)*nd= 0.02nd

sold the share for $s

paid a fee of $11

Her net proceeds algebraically will be

Net proceed= s-nd-11-0.02nd

collect like terms

Net proceed= s-(nd-0.02nd)-11

Net proceed= s-0.98nd-11

5 0
1 year ago
An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by
GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis H_0 : \mu_1 - \mu_2 >2,

and the alternative hypothesis H_1: \mu_1 - \mu_2 \leq 2.

We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

s_p^2 = \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2} = 20.05,

where n_1 = 12, n_2 =10, s_1 =4, s_2 = 5.

The mean of material 1 and material 2 are \mu_1 =85, \mu_2=81 respectively and mean difference d is equal to 4. The hypothesize difference d_0 is equal to 2.

To find the T-score, we use the following formula

T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}

Substituting all the values into the T-score formula gives us T = 1.04, and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

6 0
1 year ago
Leona purchased a $1,000 bond having a quoted price of 99.875. She had to pay a 5.5% brokerage fee (of the selling price). What
Zina [86]

Answer:

The total cost of the bond is none of the given choices.

Step-by-step explanation:

The selling price of a $1000 bond  =   $99.875

The brokerage fee = 5.5 %

Now, 5.5%  of $99.875 =  \frac{5.5}{100}  \times 99.875 = 5.493

So, the brokerage fee = $5.493

Now, to find out the total cost of the bond:

Total Cost  = The selling Price + Brokerage Price

                  = $99.875 + $5.493

                  =  $105.368

or, the total price of the $1000 bond is $ 105.368.

Hence,  the total cost of the bond is none of the given choices.

7 0
2 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?
Basile [38]

Answer:

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = -b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = -8

It becomes

x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

x = - 3 ± √9 - 4(- 16)]/2×2

x = [- 3 ± √9 + 64]/2×2

x = [- 3 ± √73]/4

x = [- 3 ± 8.544]/4

x = (-3 + 8.544) /4 or x = (-3 - 8.544) / 4

x = 5.544/4 or - 11.544/4

x = 1.386 or x = - 2.886

The positive solution is 1.39 rounded up to the nearest hundredth

8 0
2 years ago
Read 2 more answers
Henri has $24,000 invested in stocks and bonds. The amount in stocks is $6,000 more than three times the amount in bonds. Call t
makvit [3.9K]

Answer:

The solve of that problem is that Hernry invested $18.000 in stocks and $6.000 in bonds.

Step-by-step explanation:

First, to explain you have to do a multiplication about 6 on three. Like three times more than bonds, the result is 18. Then you have to do a  subtraction on $24.000 less $18.000, and the result is $6.000, so six is the amount on bonds. And is three times less than stocks, like the questions ask.

4 0
2 years ago
Read 3 more answers
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