F^1(-2) = 2(-2) = -4
f(-4) = 1/2 * -4 = -2
f(f^-1(x)) = x so answer is -2
Answer:
(a) 12π in
(b) 53.5 in
(c) 96 grams
Step-by-step explanation:
In the figure attached, the ornament is shown
(a) four three-quarter circles is equivalent to 4*3/4 = 3 circles. The perimeter of a circle is the total length of the circular portions.
Perimeter of each circle: 2*π*r
The radius is 2 in long, then for 3 circles:
Perimeter = 3*2*π*2 = 12π in
(b) Perimeter of square: 4*side length
The side length of the square is 4 in, then:
Total length of wire needed = 4*4 + 12π = 53.5 in
(c) The wire weighs 1.8 grams per inch, then:
total weight of the ornament = 1.8 grams/in * 53.5 in = 96 grams
Answer:
That (blank) is 9.
Step-by-step explanation:
Please write 8x^2 - 48x = -104, with " ^ " indicating exponentiation. Thanks.
This sounds like a perfect example of "completing the square."
First, factor 8x^2 - 48x = -104: 8(x^2 - 6x = -13).
If we focus SOLELY on x^2 - 6x = -13, it's just a little easier to "complete the square." Take half of the coefficient of x (which here is -6), and square that result (which here is (-3)^2, or 9. Now add 9 both sides of x^2 - 6x = -13:
x^2 - 6x + 9 = -13 + 9. Note: The "blank" in the problem statement is 9.
We could go ahead and solve this, tho' we weren't asked to do so. Rewrite x^2 - 6x + 9 as (x - 3)^2:
x^2 - 6x = -13 then becomes (x - 3)^2 = 4. To solve for x, take the sqrt of both sides of this latest result, obtaining x - 3 = plus or minus 2. Add 3 to both sides to isolate x: x = 3 plus or minus 2.
Thus, x = 5 or x = 1.
Lol idk.......................................................................................................
1. It is the subset of a group - Group sample.
2. It equally favors all members of a group sample
- Random sample.
3. It collects data on members of a group - Survey.
4. It does not equally favor all members of a group - Biased sample.
5. It includes all members of a group
- Population.
6. It analyzes data collected from a group - Mean.
I have matched all concepts in accordance with statistical use, hope it helps.
