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2 years ago

Factor 28+56t+28w28+56t+28w28, plus, 56, t, plus, 28, w to identify the equivalent expressions. Choose 2 answers:

Mathematics

1 answer:

Effectus [21]2 years ago

6 0

Answer: The factorization of $28+56t+28w$ $=28(1+2t+w)$

The factors of $28+56t+28w$ are 28 and 1+2t+w.

Step-by-step explanation:

The given expression : $28+56t+28w$

To factorize it, we need to find the common factor.

As 56 can be written as 2 x 28.

So, the above expression would become

$28+2\times28t+28w$

Now, taking 28 as common from all the terms, we will get

$28(1+2t+w)$

Thus, the factorization of $28+56t+28w$ $=28(1+2t+w)$

And the factors of $28+56t+28w$ are 28 and 1+2t+w.

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The arena wants to estimate the previous two month’s ticket-sale income. In total, 71,115 people attended different events at th

AveGali [126]

Hey there,
Total no. of people= 71,115
Average cost of ticket = 21.15 pounds
Total ticket income= 71,115 x 21.15
= 1,504,082.25 pounds

Hope this helps :))

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2 years ago

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza do

xz_007 [3.2K]

Answer:

The minimum width of the placemat is 10 inches.

Step-by-step explanation:

Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:

$w = D$

Where:

$w$ - Width of the placemat, measured in inches.

$D$ - Diameter of pizza, measured in inches.

The area of the pizza, measured in square inches, is determined by this formula:

$A = \frac{\pi}{4} \cdot D^{2}$

The diameter is cleared afterwards:

$D = \sqrt{\frac{4\cdot A}{\pi} }$

If $A = 78.5\,in^{2}$ and $\pi = 3.14$ , then:

$D = \sqrt{\frac{4\cdot (78.5\,in^{2})}{3.14} }$

$D = 10\,in$

The minimum width of the placemat is 10 inches.

4 0

2 years ago

Read 2 more answers

2. Let f(x) = 3x² -x+5, find f(x+1)

Anna11 [10]

Answer:

f(x + 1) = 3x² + 5x + 7

Step-by-step explanation:

To find f(x + 1), substitute x = x + 1 into f(x), that is

f(x + 1) = 3(x + 1)² - (x + 1) + 5 ← expand (x + 1)² using FOIL

= 3(x² + 2x + 1) - x - 1 + 5 ← distribute parenthesis by 3

= 3x² + 6x + 3 - x - 1 + 5 ← collect like terms

= 3x² + 5x + 7

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2 years ago

Maria has 14 pencils, Ted has 9 pencils, Tom has 12 pencils, Lucinda has 13 pencils, and Jumana has 12 pencils. How can they red

Likurg_2 [28]

HEY THERE !!

GIVEN :- Maria has 14 pencils, Ted has 9 pencils, Tom has 12 pencils, Lucinda has 13 pencils, and Jumana has 12 pencils.

The sum of all pencils are 60 and the number of persons are 5 .

So 60/5= 12
The no. of pencil which every person has after redistribution is 12 .

HOPE IT HELPED YOU.

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2 years ago

Read 2 more answers

Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) i

Vaselesa [24]

Complete question:

Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?

Answer:

Here,

Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)

We are also told only 10 participants are available.

All 10 participants are being exposed to all five levels of the color variable in the same order.

Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.

Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.

But using counterbalancing technique, Dr. Lyte can avoid such an error.

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2 years ago