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Lemur [1.5K]
2 years ago
9

Broccoli costs $1.50 per pound at a store. How much money does 32 ounces of broccoli cost?

Mathematics
2 answers:
larisa [96]2 years ago
8 0
There are 16 ounces in a pound.
16+16 = 32.
So 32 ounces is 2 pounds for a total $3.00.
Hope it helps!
vitfil [10]2 years ago
6 0

Answer:-Cost of 32 ounces of broccoli= $


Explanation:-

We know that 1 ounce=\frac{1}{16}\text{ pound}

\Rightarrow32\text{ ounces}=32\times\frac{1}{16}\text{ pound}=2\text{ pounds}

Given:-  Cost of 1 pound of broccoli = $1.50

⇒Cost of 32 ounces of broccoli= Cost of 2 pounds broccoli=2×$1.50 =$3

Therefore, Cost of 32 ounces of broccoli= $3.

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You divide 26 by 6, and you get 4 1/3, so I guess Montel will need 5 pages.
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The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T
Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. In this problem, \sigma = 0.25

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

M = z*\frac{\sigma}{\sqrt{n}}

0.1 = 1.96*\frac{0.25}{\sqrt{n}}

0.1\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.1}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}

n = 24.01

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

M = z*\frac{\sigma}{\sqrt{n}}

0.06 = 1.96*\frac{0.25}{\sqrt{n}}

0.06\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.06}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}

n = 66.7

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

M = z*\frac{\sigma}{\sqrt{n}}

0.05 = 1.96*\frac{0.25}{\sqrt{n}}

0.05\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.05}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}

n = 96.04

Rounding up, 97

8 0
1 year ago
M∠1=45° and m∠3=65°
7nadin3 [17]

Answer:

In Right Δ ABC with right angle B,

∠A=(3 x -8)°, ∠B=90°, ∠C=(x-2)°

∠A+∠B+∠C=180°[∠ sum property of triangle]

3 x-8+90 + x-2=180

Adding and subtracting like terms

4 x-10+90=180

4 x+80=180

4 x=180-80

4 x=100

x=100/4

x=25°

∠A=3×25-8=75-8=67°




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Which situation involves descriptive statistics?
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They all involve descriptive statistics.
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Jimmy went to the toy store. He saw 23 wooden trains and 41 plastic trains.how many more plastic trains than wooden trains did h
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To find out d answer to dis we need to subtract d amount of plastic trains by d amount of wooden trains. d answer will be d answer to your question. lets do it:-

41 - 23 = 18
Jimmy sees 18 more plastic trains than wooden trains.

CHECK OUR WORK:-

18 + 23 = 41
We were RIGHT!!

So, Jimmy sees 18 more plastic trains than wooden trains.

Hope I helped ya!! xD 
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