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Lemur [1.5K]
2 years ago
9

Broccoli costs $1.50 per pound at a store. How much money does 32 ounces of broccoli cost?

Mathematics
2 answers:
larisa [96]2 years ago
8 0
There are 16 ounces in a pound.
16+16 = 32.
So 32 ounces is 2 pounds for a total $3.00.
Hope it helps!
vitfil [10]2 years ago
6 0

Answer:-Cost of 32 ounces of broccoli= $


Explanation:-

We know that 1 ounce=\frac{1}{16}\text{ pound}

\Rightarrow32\text{ ounces}=32\times\frac{1}{16}\text{ pound}=2\text{ pounds}

Given:-  Cost of 1 pound of broccoli = $1.50

⇒Cost of 32 ounces of broccoli= Cost of 2 pounds broccoli=2×$1.50 =$3

Therefore, Cost of 32 ounces of broccoli= $3.

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ABCD is a rectangular garden plot . P is a water tap find the distance from P to C
choli [55]

Answer:

PC  = 40/7 = 5.714 m

Step-by-step explanation:

i) the solution can be found by using similarity of triangles.

ii) therefore we can see that \frac{PC}{8}  = \frac{5}{7}

iii) therefore PC  = 40 / 7 = 5.714 m

8 0
2 years ago
Disney held a breakfast for parents and their children to eat with Mickey mouse. adult tickets cost $17.95 and children's ticket
RUDIKE [14]

Answer:

The number of children attending = 324

The number of adults attending  = 176.

Step-by-step explanation:

Here, the total number of people attending = 500

Let us assume the umber of children attending the breakfast = m

So, the number of adults attending the breakfast = 500 - m

Cost of ticket for each children  = $12.95

So, the cost of m children's tickets = m x ( Cost of 1 children ticket)

=  m x ( $12.95)  = 12.95 m .... (1)

Cost of ticket for each adult  = $17.95

So, the cost of (500 -m)  adults's tickets

= (500 - m) x ( Cost of 1 adult ticket)    = (500 -m) x ( $17.95)  

 = 8,975 - 17.95 m     .... (2)

Now, the total earnings from the total ticket sold = $7355

So, The earning from ( Adult's + children's tickets)  = $7355

⇒  12.95 m  +  8,975 - 17.95 m = $7355

or, - 5 m = 7355 - 8975 =   -1620

or, m = 1620/5 = 324

⇒  m =324

Hence the number of children attending =  m = 324

The number of adults attending = 500 - m = 500 - 324 = 176.

7 0
2 years ago
Adam is using the equation (x)(x + 2) = 255 to find two consecutive odd integers with a product of 255. When Adam solves the pro
kondaur [170]
\bf (x)(x+2)=255\implies x^2+2x=255\implies x^2+2x-255=y
\\\\
\textit{setting y=0}\implies x^2+2x-255=0
\\\\
\textit{now, factoring that}
\\\\
(x+17)(x-15)=0\implies 
\begin{cases}
x=-17\\
x=15
\end{cases}

notice the picture of the graph added here
low and behold, x = -17, y is 0, and x= 15, y is 0
the graph is touching the x-axis, an x-intercept
or so-called, a "solution"

3 0
2 years ago
Read 2 more answers
Bo paid bills with 1/2 of his paycheck snd put 1/5 of the remainder in savings. The rest of his paycheck he divided equally amon
frutty [35]
1/2 + 1/5(1/2) = 1/2 + 1/10 = 5/10 + 1/10 = 6/10....this leaves 4/10 (reduces to 2/5) for his children.

(2/5) / 3 = 2/5 * 1/3 = 2/15 for each child <== A

400 in each childs account.....thats (400 * 3) = 1200 ...
2/5 of what is 1200 =
2/5x = 1200
x = 1200 * 5/2
x = 6000/2
x = 3000 <== B

check...
total pay is 3000
1/2 for bills.....- 1500
1/5(-1500) = -1500/5 = -300 ....for savings
3000 - (1500 + 300) = 3000 - 1800 = 1200...remaining for the children
1200/3 = 400 ...for each child.

so ur answers are :
A. 2/15 in each childs account
B. original paycheck = $ 3000


3 0
2 years ago
Read 2 more answers
Which of the following functions is graphed below?
dalvyx [7]

Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

- Add 4 to both sides

∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix + 5I = 4

∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

- OR

∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

5 0
2 years ago
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