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2 years ago

The data show the number of pieces of mail delivered to a single home address each day for three weeks.

Mathematics

2 answers:

cricket20 [7]2 years ago

6 0

<span> the answers are B and D
hope this helps out :}</span>

alisha [4.7K]2 years ago

6 0

it b and d

..................

B. A dot plot would show 7 points for numbers greater than 2.

D. A histogram would have a maximum of 7 bars.

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Consider the system of linear equations. x + y = 9.0 0.50 x + 0.20 y = 4.05 Find the values of x and y .

mixas84 [53]

Answer:

x=7.5

y=1.5

Step-by-step explanation:

$x + y = 9.0$

subtract x from both sides

$y=9-x$

$0.50x + 0.20y= 4.05$

$0.50 x +0.20(9-x)= 4.05$

$0.50x+1.8-0.2x= 4.05$

combine like terms

$0.30x+1.8= 4.05$

subtract 1.8 from both sides

$0.30x=2.25$

divide both sides by 0.3

x=7.5

$y=9-x$

$y=9-7.5$

y=1.5

4 0

2 years ago

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assig

Keith_Richards [23]

Answer:

1. Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

2. D. 36

3. C. 34

4. B. 1.059

5. B. 8.02

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part 1

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

Part 2

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

We need to find the mean for each group first and the grand mean.

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

If we apply the before formula we can find the mean for each group

$\bar X_A = 27$ , $\bar X_B = 24$ , $\bar X_C = 30$ . And the grand mean $\bar X = 27$

Now we can find the sum of squares between:

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

Each group have a sample size of 4 so then $n_j =4$

$SS_{between}=SS_{model}=4(27-27)^2 +4(24-27)^2 +4(30-27)^2=72$

The degrees of freedom for the variation Between is given by $df_{between}=k-1=3-1=2$ , Where k the number of groups k=3.

Now we can find the mean square between treatments (MSTR) we just need to use this formula:

$MSTR=\frac{SS_{between}}{k-1}=\frac{72}{2}=36$

D. 36

Part 3

For the mean square within treatments value first we need to find the sum of squares within and the degrees of freedom.

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

$SS_{error}=(20-27)^2 +(30-27)^2 +(25-27)^2 +(33-27)^2 +(22-24)^2 +(26-24)^2 +(20-24)^2 +(28-24)^2 +(40-30)^2 +(30-30)^2 +(28-30)^2 +(22-30)^2 =306$

And the degrees of freedom are given by:

$df_{within}=N-k =3*4 -3 = 12-3=9$ . N represent the total number of individuals we have 3 groups each one with a size of 4 individuals. And k the number of groups k=3.

And now we can find the mean square within treatments:

$MSE=\frac{SS_{within}}{N-k}=\frac{306}{9}=34$

C. 34

Part 4

The test statistic F is given by this formula:

$F=\frac{MSTR}{MSE}=\frac{36}{34}=1.059$

B. 1.059

Part 5

The critical value is from a F distribution with degrees of freedom in the numerator of 2 and on the denominator of 9 such that we have 0.01 of the area in the distribution on the right.

And we can use excel to find this critical value with this function:

"=F.INV(1-0.01,2,9)"

And we will see that the critical value is $F_{crit}=8.02$

B. 8.02

5 0

2 years ago

Kayson mixes 300300300 milliliters (\text{mL})(mL)left parenthesis, start text, m, L, end text, right parenthesis of spinach, 20

Georgia [21]

Answer:

Total, T = (300s+200b+42d) mg

Step-by-step explanation:

Given that,

Kayson mixes 300 mL spinach, 200 mL of berries, and 42 mL of dressing to make a salad.

There are s mg of vitamin C per mL of spinach, b mg per mL of berries, and d mg per mL of dressing.

In 300 mL of spinach vitamin C is = (300 s)mg

In 200 mL of berries vitamin C is = (200 b)mg

In 42 mL of salad vitamin C is = (42 d)mg

It means that, total mg of vitamin C is :

Total, T = (300s+200b+42d) mg

Hence, this is the required solution.

4 0

2 years ago

Which of the number(s) below are potential roots of the function? p(x) = x4 + 22x2 – 16x – 12

Neporo4naja [7]

Complete question is;

Which of the number(s) below are potential roots of the function? p(x) = x⁴ + 22x² – 16x – 12

A) ±6

B) ±1

C) ±3

D) ±8

Answer:

Options A, B & C: ±6, ±1, ±3

Step-by-step explanation:

We are given the polynomial;

p(x) = x⁴ + 22x² – 16x – 12

Now, the potential roots will be all the rational numbers equivalent of p/q.

Where;

p are the factors of the constant term of the polynomial

q are the factors of the leading coefficient of the polynomial

Now, in the given polynomial, the constant term is seen as -12 while leading coefficient is 1 which is the coefficient of x⁴.

We know that factors of 12 are any of:

±1, ±2, ±3, ±4, ±6 and ±12

While possible factors of 1 is just ±1.

Thus, all the potential roots of the polynomial function are;

±1, ±2, ±3, ±4, ±6 and ±12

From the options given, option A, B & C could be the potential roots.

6 0

2 years ago

Find the square. (4x – 6y3)2

Artyom0805 [142]

Answer:

16x^2 -48xy^3 +36y^6

Step-by-step explanation:

Use FOIL or the distributive property or the form of the square of a binomial to expand the square.

(4x -6y^3)(4x -6y^3) = 4x(4x -6y^3) -6y^3(4x -6y^3)

= (4x)^2 -(4x)(6y^3) -(6y^3)(4x) +(6y^3)^2

= 16x^2 -48xy^3 +36y^6

_____

The form referred to above is ...

(a +b)^2 = a^2 +2ab +b^2

6 0

1 year ago