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Katarina [22]
1 year ago
15

Consider the system of linear equations. x + y = 9.0 0.50 x + 0.20 y = 4.05 Find the values of x and y .

Mathematics
1 answer:
mixas84 [53]1 year ago
4 0

Answer:

x=7.5

y=1.5

Step-by-step explanation:

x + y = 9.0

subtract x from both sides

y=9-x

0.50x + 0.20y= 4.05

0.50 x +0.20(9-x)= 4.05

0.50x+1.8-0.2x= 4.05

combine like terms

0.30x+1.8= 4.05

subtract 1.8 from both sides

0.30x=2.25

divide both sides by 0.3

x=7.5

y=9-x

y=9-7.5

y=1.5

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Answer:

The probability that the pirate misses the captain's ship but the captain hits = 0.514

Step-by-step explanation:

Let A be the event that the captain hits the pirate ship

The probability of the captain hitting the pirate ship, P(A) = 3/5

Let B be the event that the pirate hits the captain's ship

The probability of the pirate hitting the captain's ship P(B) = 1/7

The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)

P'(B) = 1 - 1/7 = 6/7

The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7

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2 years ago
Find the sum of the first 63 terms of –19, -13, -7 …
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The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

Given n = 63 and we found a = -19 and d = 6

\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)

\implies S_6_3 = \frac{63}{2}(-38 + (62)6)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

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The Sum of First 63 terms is 10521

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Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

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Thus, the value of x that gives the maximum transmission is 1/√e.

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It is 12.375 feet long.

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