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2 years ago

13

Light bulbs cost £2.30 each. Yasmin buys as many as she can with £20. How much change should she get? Give your answer in pounds

, £.

2 answers:

djyliett [7]2 years ago

6 0

Answer:

£1.6

Step-by-step explanation:

£20 ÷ £2.3= 8 remainder 1.6

change= £1.6

Kaylis [27]2 years ago

4 0

Answer:

1.60 euros

Step-by-step explanation:

2.30 times 8 = 18.40

20-18.40 = 1.60

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Raleigh went to a gaming arcade for his birthday. His parents gave him $55 to spend. He purchased $14.25 in food and drinks, and

xenn [34]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Total amount to spend = $55

Amount of food and drinks purchased = $14.25

Amount put on gaming card = $(55 - 14.25) = $40.75

Cost per game = $1.25

Number of games (g) he can play

Number of games g:

Amount put on gaming card / cost per game

= $40.75 / $1.25

= 32.6 games

g ≤ 32

6 0

2 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago

Jenny is taking a vacation to Florida. She travels 70 kilometers per hour for 2 hours, and 63 kilometers per hour for 5 hours. O

Helga [31]

Jenny traveled 70 km/h over 2 hours and 63 km/h over 5 hours. Her travel time was a total of 7 hours.

We need to find out how far she traveled during this 7-hour period.

70 km/h * 2 h = 140 km
63 km/h * 5 h = 315 km

Then, we can add 140 km and 315 km to get a total distance traveled of <em>455 km/h.</em>

We were asked to find the average <em>speed.</em> We can find it now, since we have total distance traveled (455 km) and total time taken (7 hours).

Then,
455km / 7h = 65 km/h.

6 0

2 years ago

Option A to buy has a total cost of 20,579 dollars, up-front cost of 2,500 dollars, monthly payment of 338 dollars for 60 months

Vladimir [108]

Answer:

B

Step-by-step explanation:

it B pls mark me i calculated it 4 time pls

3 0

2 years ago

Divide 32x4 − 12x2 + 7x by 2x.

Katen [24]

(32x⁴ - 12x² + 7x) / 2x

32x⁴/2x - 12x²/2x + 7x/2x

16x³ - 6x + 7/2

4 0

2 years ago