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elena55 [62]
2 years ago
5

A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the

square is StartFraction pi r squared Over 4 r squared EndFraction or StartFraction pi Over 4 EndFraction.
A cylinder is inside of a square prism. The height of the cylinder is h and the radius is r. The base length of the pyramid is 2 r.

Since the area of the circle is StartFraction pi Over 4 EndFraction the area of the square, the volume of the cylinder equals

StartFraction pi Over 2 EndFraction the volume of the prism or StartFraction pi Over 2 EndFraction(2r)(h) or πrh.
StartFraction pi Over 2 EndFraction the volume of the prism or StartFraction pi Over 2 EndFraction(4r2)(h) or 2πrh.
StartFraction pi Over 4 EndFraction the volume of the prism or StartFraction pi Over 4 EndFraction(2r)(h) or StartFraction pi Over 4 EndFractionr2h.
StartFraction pi Over 4 EndFraction the volume of the prism or StartFraction pi Over 4 EndFraction(4r2)(h) or Pir2h.
Mathematics
2 answers:
tensa zangetsu [6.8K]2 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

Eva8 [605]2 years ago
3 0

Answer:

d

Step-by-step explanation:

i took the test

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Find the difference: square root of 20 - square root of 80
Mamont248 [21]

Answer:

-2\sqrt{5}

Step-by-step explanation:

\sqrt{20} = \sqrt{10*2} = \sqrt{5 * 2 *2} = \sqrt{2^2 * 5} = 2\sqrt{5}   \\\\\sqrt{80} = \sqrt{20*4} = \sqrt{5*4 *4} = \sqrt{4^2 * 5} = 4\sqrt{5}   \\\\2\sqrt{5} - 4\sqrt{5} = -2\sqrt{5}

8 0
2 years ago
Read 2 more answers
A quality-control inspector is testing a batch of printed circuit boards to see wheater they are capable of performing in a high
avanturin [10]

Answer:

see explaination

Step-by-step explanation:

Here the null hypothesis is that the PCB survives against the alternate that the PCB 'does not survive'. The test says that the PCB will survice if it is classified as 'good'; or, it will not survive if it is classifies as 'bad'.

a. The Type II error is the error committed when a PCB which cannot actually survive is classified as 'good'.

b. Therefore P(Type II error) = P(The PCB is classified as 'good' | PCB does not survives) = 0.03.

6 0
2 years ago
The Metro theater has 20 rows of seats with 18 seats in each row Tickets cost $5 The theaters income in dollars if all seats are
Olin [163]
Answer: $1800

The theater income will be the total of audience multiplied by the ticket cost.  To answer this question, you need to determine the total audience count. Assuming all the seats are occupied then:
Total audience= row of seats x seats/ row = 20x18 people = 360 people

After that the income would be:
Income = audience x ticket cost
Income= 360 people x $5 / people= $1800
3 0
2 years ago
Tennessee has a population of about 6,495,978. Its territory can be modeled as a trapezoid, as shown in the figure. Each unit on
kotegsom [21]

Answer:

The population density is 150 persons per square mile

Step-by-step explanation:

Firstly, we need to calculate the area of the trapezoid.

Mathematically, the area of a trapezoid is

(a+b)/2 * h

from the grid, we can obtain the lengths

on the x-axis , each line is 40(200/5 thin lines)

on the y-axis, each thin line also is 40(200/5 thin lines)

thus a = (8 * 40) = 320

b = (10* 40) = 400

h = (3 * 40) = 120

Inserting this into the area equation, we have the area of the trapezoid as (320 + 400)/2 * 120 = 43,200 units

since each unit = 1 mile, the area of Tennessee = 43,200 units

The population density is thus ; 6,495,978/43,200= which is approximately 150 persons per square mile

3 0
2 years ago
The swimming instructor has a list of 152 students who have signed up for swimming lessons. The swimming instructor can register
andrew-mc [135]

Answer:

2. 13

Step-by-step explanation:

The least number of classes need for all of the students to be registered in a class is 13 since you want all of the stuednts to be registered so no one should be left out. If we do 12*12 (12 students in each class and there are 12 classes), that would only let 144 students take the swimming classes and 8 students would be left out. We don't want that though since we want all of the students to be registered. So let's go to 12*13 (12 students in each class and  there are 13 classes), that would let 156 students take the swimming class. 156>152 so therefore, 13 classes would allow for all 152 students to be registered and it is the least number of classes needed for all the students to be registered in a class (plus you would have 4 seats left for anyone who wants to register in the future but the remainder doesn't matter).  

6 0
2 years ago
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