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In-s [12.5K]
1 year ago
15

The diagram shown here represents

Mathematics
2 answers:
valentina_108 [34]1 year ago
5 0

Answer:  B) two intersecting planes.

Step-by-step explanation:

Definitions:

A line is a one -dimensional geometric figure that extends infinitely in both directions. It has only length but no width.

The intersection of two line is a point.

A plane is a two dimensional flat surface (like a sheet of paper)  and it extends infinitely . It has both length and width .

The intersection of two plane is a line.

By considering the given figure , we can easily see that the two planes ( ∵they have both length and width) are intersecting each other and the intersection is a line.

It means the correct answer regarding the given diagram : B) two intersecting planes.

Marysya12 [62]1 year ago
3 0

Answer:

THE ANSWER IS B

Step-by-step explanation:


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A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the pr
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Answer:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

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Option A

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The null hypothesis is: U <= 50%

The alternative is: U > 50%

Thus, the principal could have committed an error by rejecting null hypothesis and concluding that more than 50% of students want earlier lunch, when in actuality 50% or less want earlier lunch.

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Given:

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