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padilas [110]
1 year ago
7

Malcolm can run a race at a speed of 6 minutes per mile, while Joshua runs at 8 minutes per mile. In a 10-mile race, how many mi

nutes after Malcolm crosses the finish line will Joshua cross the finish line if they start the race together?
Mathematics
1 answer:
mylen [45]1 year ago
5 0

Answer:

  • 20 min

Explanation:

The time to cross the finish line may be found using the speed vs. time equation:

  • speed = distance / time

From which you can solve for time:

  • time = distance / speed.

Using the last equation, you can find the difference in the times for Malcolm and Joshua, but, since the speed must be expressed in miles per minutes, and the given data are minutes per mile, first you must convert the data.

Miles per minute is the inverse of minutes per mile, so the corresponding speeds are:

  • Malcolm's speed: 1 / (6 min/mile) = (1/6) miles/min

  • Joshua's speed: 1 / (8 min/mile) = (1/8) miles/min

  • Time for Malcom: 10 miles / [ 1/ (6 miles/min) ] = 10/(1/6) min = 60 min

  • Time for Joshua: 10 miles / [ 1/ ( 8 miles/min) ] = 10/(1/8) min = 80 min

  • Difference in times: 80 min - 60 min = 20 min

Hence, Joshua will cross the finish line 20 minutes after Malcolm crosses the finish line.

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Match each pair of points to the equation of the line that is parallel to the line passing through the points.
Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to


m=\frac{y2-y1}{x2-x1}


we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point B(5,2)\ C(7,-5)

Find the slope BC

Substitute the values in the formula

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


so

The equation y=-3.5x-15 is parallel to the line passing through the points B(5,2)\ C(7,-5)

therefore

<u>the answer Part A) is</u>

B(5,2)\ C(7,-5) ------> y=-3.5x-15

<u>Case B)</u> Point D(11,6)\ E(5,9)

Find the slope DE

Substitute the values in the formula

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


so

The equation y=-0.5x-3 is parallel to the line passing through the points D(11,6)\ E(5,9)

therefore

<u>the answer Part B) is</u>

D(11,6)\ E(5,9) ------> y=-0.5x-3

<u>Case C)</u> Point F(-7,12)\ G(3,-8)

Find the slope FG

Substitute the values in the formula

m=\frac{-8-12}{3+7}  

m=\frac{-20}{10}


m=-2


so

Any linear equation with slope m=-2 will be parallel to the line passing through the points F(-7,12)\ G(3,-8)

<u>Case D)</u> Point H(4,4)\ I(8,9)

Find the slope HI

Substitute the values in the formula

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


so

The equation y=1.25x+4 is parallel to the line passing through the points H(4,4)\ I(8,9)

therefore

<u>the answer Part D) is</u>

H(4,4)\ I(8,9) ------> y=1.25x+4

<u>Case E)</u> Point J(7,2)\ K(-9,8)

Find the slope JK

Substitute the values in the formula

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


so

Any linear equation with slope m=-0.375 will be parallel to the line passing through the points  J(7,2)\ K(-9,8)

<u>Case F)</u> Point L(5,-7)\ M(4,-12)

Find the slope LM

Substitute the values in the formula

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


m=5


so

The equation y=5x+19 is parallel to the line passing through the points L(5,-7)\ M(4,-12)

therefore

<u>the answer Part F) is</u>

L(5,-7)\ M(4,-12) ------>  y=5x+19




8 0
1 year ago
Read 2 more answers
If an object is projected upward with an initial velocity of 129 ft per sec, its height h after t seconds is h = -16^2+123t. Fin
elena-s [515]

This problem can be solved directly by neglecting the initial velocity given. All we have to do is to plug in t = 4 in the given equation. That is:

h = -16^2 + 123 * 4

h = 236 ft

3 0
2 years ago
Read 2 more answers
Use complete sentences to explain how the coordinate plane is a useful tool for geometric proofs.
Masja [62]

the facilitate verification is a proof of a geometric hypothesis which utilizes "summed up" indicates on the Cartesian Plane make a contention. 


The strategy for the most part includes doling out factors to the directions of at least one focuses, and afterward utilizing these factors in the midpoint or separation equations . 


For instance, the accompanying is an arrange evidence of the Triangle Midsegment Theorem , which expresses that the fragment interfacing the midpoints of two sides of a triangle is parallel to the third side and precisely a large portion of the length.

8 0
2 years ago
A recipe calls for One-fourth cup of broth. The largest volume-measuring tool that Tabitha has is a teaspoon. She knows that the
djverab [1.8K]

<u>Answer:</u>

Tabitha will use 12 teaspoons.

<u>Explanation: </u>

According to the question, Tabitha has a largest volume-measuring tool teaspoon, and she wants to use one-fourth cup of broth.

Given that 1 cup consists of 16 tablespoons and 1 tablespoon has 3 teaspoons.

From the data, we can calculate that;

16 tablespoons will be equal to (3*16) = 48 teaspoons.

Therefore, 1 cup = 48 teaspoons.

Substituting the data and we can calculate that 1/4 cup = 48/4 = 12 teaspoons.

5 0
1 year ago
The figure below shows the dimensions of a city park in feet. Shannon thinks the area of city park is 73,084 square feet. Do you
Andreyy89

Answer:

We need to solve for the 4th side

4th side base = 75.5 -60.5 = 10 feet

4th side height = 16

4th side LENGTH^2 = 10^2 + 16^2

4th side = sq root (356) = 18.8679622641

Trapezoid Area = [(sum of the bases) / 2 ] * height

Trapezoid Area = [(136)/2] * 16

Trapezoid Area = 1,088 square feet, which is MUCH smaller

than 73,084

Step-by-step explanation:

3 0
1 year ago
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