Answer: y=12 x=28
Explanation:
x=Amount of Small Lanterns y=Amount of Large Lanterns
25x+40y=1180
x+y=40
x=40-y
25(40-y)+40y=1180
1000-25y+40y=1180
1000+15y=1180
15y=180
y=12
x+12=40
x=28
Answer:
x=15
Step-by-step explanation:
subtract 1 from both sides so you are left with 2x=5x-45
then subtract 5x from both sides and you have -3x=-45
then finally divide -3 from -45 to get x=15
<span>The table should have the titles: "Grades" for the horizontal axis and "Gender" for the vertical axis. The values for "Grades" are A, B, & C. The values for "Gender" are Boys and Girls. The information contained within the table should be as follows: 12 boys received an A, 24 boys received a B, 12 boys received a C; 16 girls received an A, 30 girls received a B, and 12 girls received a C. There should be a "Total" row at beneath the "Gender" section showing that there were 28 A's, 54 B's, and 24 C's. There should be an additional "Total" column at the end of "Grades" showing that there are 48 boys and 52 girls.</span>
Answer:
a. 80 students
b. 92 students
Step-by-step explanation:
Represent arts students with A and Dance students with D.
So, we have,
n(A) = 35
n(D) = 57
Required
Determine n(A or D)
Solving (a):
Here, we have:
n(A and D) = 12
n(A or D) is calculated as thus:
n(A or D) = n(A) + n(D) - n(A and D)
n(A or D) = 35 + 57 - 12
n(A or D) = 80
b. From the given details
n(A and D) = 0 because both students are not mixed up as in (a) above
Using the same formula as (a).
n(A or D) = n(A) + n(D) - n(A and D)
n(A or D) = 35 + 57 - 0
n(A or D) = 92